Answer:
0.14 J
Explanation:
The maximum velocity is the amplitude times the angular frequency.
vmax = Aω
ω = vmax / A
ω = (3.2 m/s) / (0.06 m)
ω = 53.3 rad/s
For a spring-mass system:
ω = √(k / m)
ω² = k / m
k = ω²m
k = (53.3 rad/s)² (0.050 kg)
k = 142 N/m
The elastic potential energy is:
EE = ½ kx²
EE = ½ (142 N/m) (0.044 m)²
EE = 0.14 J
Answer:
Q = 47.06 degrees
Explanation:
Given:
- The transmitted intensity I = 0.464 I_o
- Incident Intensity I = I_o
Find:
What angle should the principle axis make with respect to the incident polarization
Solution:
- The relation of transmitted Intensity I to to the incident intensity I_o on a plane paper with its principle axis is given by:
I = I_o * cos^2 (Q)
- Where Q is the angle between the Incident polarized Light and its angle with the principle axis. Hence, Using the relation given above:
Q = cos ^-1 (sqrt (I / I_o))
- Plug the values in:
Q = cos^-1 ( sqrt (0.464))
Q = cos^-1 (0.6811754546)
Q = 47.06 degrees
The answer is evolution. When a specifies evolves over time they change and adapt to their environment.
Answer:
Her displacement is 35 feet. Her distance is 75 feet.
If she walks 20 ft N, 35 ft E, and 20 ft S, it makes a rectangle with one missing side, which is 35. Her displacement is therefore 35, and 20 plus 35 plus 20 equals 75, which is the distance she walked.
Hope this helps!
Answer:
The time constant becomes twice.
Explanation:
= Time constant of the L-R circuit
= Inductance of the inductor
= Resistance of the resistor
Time constant of the L-R circuit is given as
= initial time constant of the L-R circuit =
= final time constant of the L-R circuit
= Initial inductance of the inductor =
= Initial inductance of the inductor = 
For the same resistance, the time constant depend directly on the inductance, hence
