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OlgaM077 [116]
3 years ago
15

Consider a sample of helium gas in a container fitted with a piston, as pictured below. The piston is frictionless, but has a ma

ss of 10.0 kg. How many of the following processes will cause the piston to move away from the base and decrease the pressure of the gas
Physics
2 answers:
andrezito [222]3 years ago
6 0

Question:

Consider a sample of helium gas in a container fitted with a piston as pictured below. The piston is frictionless, but has a mass of 10.0 kg. How many of the following processes will cause the piston to move away from the base and decrease the pressure of the gas? Assume ideal behavior.

I. Heating the helium. II.

II. toRemoving some of the helium from the container.

III. Turning the container on its side.

IV. Decreasing the pressure outside the container.

a) 0

b) 1

c) 2

d) 3

e) 4

Answer:

Only one process will cause the piston to move which is

i) Heating the helium

Explanation:

When helium is heated it becomes less dense or lighter. Heating the helium will cause an increase in volume which will make the piston to move away from the base. When the volume finishes increasing, the piston will stop moving which in turn will make the forces on both sides of the piston balanced, so the pressure inside will balance the weight of the piston and that of the atmosphere. From that we can see that there has been a pressure change as a result of heating.

aev [14]3 years ago
3 0

Question:

Consider a sample of helium gas in a container fitted with a piston, as pictured below. The piston is frictionless, but has a mass of 10.0 kg. How many of the following processes will cause the piston to move away from the base and decrease the pressure of the gas? Assume ideal behavior.

I.

heating the helium

II.

removing some of the helium from the container

III.

turning the container on its side

IV.

decreasing the pressure outside the container

Answer:

Two of the following processes will cause the piston to move away from the base and decrease the pressure of the gas.

III and IV.

III.

turning the container on its side

IV.

decreasing the pressure outside the container

Explanation:

To answer the question, we will be required to analyze each option as follows

I.  

heating the helium

Here, assuming ideal behavior, according to Charles' law, at constant pressure the volume of a given mass of gas is directly proportional to its temperature, in  Kelvin.

Therefore, heating the helium will increase the volume of the gas and move up the piston to move away from the base. However the pressure will remain constant.

Only one condition is met

II.

removing some of the helium from the container

If the container is empty, the piston ill rest on the base of the container.

Does not meet the conditions.

III.

turning the container on its side

Here, the force of the piston on the helium gas due to grvity is removed, therefore the helium will expand and the pressure of the helium gas will be reduced as the force of the piston is no longer in effect, the volume  occupied by the gas increases, therefore the piston moves away from the base.

Both conditions are met.

IV.

decreasing the pressure outside the container

When the pressure outside the container is decreased the force due to atmospheric pressure is reduced and the helium will expand to assume a lesser equilibrium pressure while moving the piston away from the base.

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Answer:

Fossils tell us when organisms lived, as well as provide evidence for the progression and evolution of life on earth over millions of years.

Explanation:

As the world changes, plants and animals change with it. Aside from a few living fossils, the species we see today are very different from species that lived in the past. Thus, the fossil record can be used to show that organisms changed to meet new conditions. ... This is the result of evolution of species over time.

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2 years ago
An 81.5-kg man stands on a horizontal surface.
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Answer:

a)V= 0.0827 m³

b)P=181.11 x 10²  N/m²

Explanation:

Given that

m = 81.5 kg

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As we know that

Mass = Volume x Density

81.5 = V x 985

V= 0.0827 m³

The force exerted by weight = m g

 F= m g= 81.5 x 10 = 815 N      ( Take ,g= 10 m/s²)

Area ,A= 4.5 x 10⁻² m²

The Pressure P

P=\dfrac{F}{A}

P = \dfrac{815}{4.5\times 10^{-2}}\ N/m^2

P=181.11 x 10²  N/m²

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3 years ago
The membrane of a living cell can be approximated by a parallel-plate capacitor with plates of area 4.50×10−9 m2 , a plate separ
Marizza181 [45]

The energy stored in the membrane is 6.44\cdot 10^{-14} J

Explanation:

The capacitance of a parallel-plate capacitor is given by

C=\frac{k\epsilon_0 A}{d}

where

k is the dielectric constant of the material

\epsilon_0 is the vacuum permittivity

A is the area of the plates

d is the separation between the plates

For the membrane in this problem, we have

k = 4.6

A=4.50\cdot 10^{-9} m^2

d=8.1\cdot 10^{-9} m

Substituting, we find its capacitance:

C=\frac{(4.6)(8.85\cdot 10^{-12})(4.50\cdot 10^{-9})}{8.1\cdot 10^{-9}}=2.26\cdot 10^{-11} F

Now we can find the energy stored: for a capacitor, it is given by

U=\frac{1}{2}CV^2

where

C=2.26\cdot 10^{-11} F is the capacitance

V=7.55\cdot 10^{-2} V is the potential difference

Substituting,

U=\frac{1}{2}(2.26\cdot 10^{-11} F)(7.55\cdot 10^{-2})^2=6.44\cdot 10^{-14} J

Learn more about capacitors:

brainly.com/question/10427437

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NASA is concerned about the ability of a future lunar outpost to store the supplies necessary to support the astronauts the supp
IRINA_888 [86]

Complete question :

NASA is concerned about the ability of a future lunar outpost to store the supplies necessary to support the astronauts the supply storage area of the lunar outpost where gravity is 1.63m/s/s can only support 1 x 10 over 5 N. What is the maximum WEIGHT of supplies, as measured on EARTH, NASA should plan on sending to the lunar outpost?

Answer:

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Explanation:

Given that :

Acceleration due to gravity at lunar outpost = 1.6m/s²

Supported Weight of supplies = 1 * 10^5 N

Acceleration due to gravity on the earth surface = 9.8m/s²

Maximum weight of supplies as measured on EARTH :

Ratio of earth gravity to lunar post gravity:

(Earth gravity / Lunar post gravity) ;

(9.8 / 1.63) = 6.01

Hence, maximum weight of supplies as measured on EARTH should be :

6.01 * (1 × 10^5)

6.01 × 10^5

= 601000 N

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