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OlgaM077 [116]
3 years ago
15

Consider a sample of helium gas in a container fitted with a piston, as pictured below. The piston is frictionless, but has a ma

ss of 10.0 kg. How many of the following processes will cause the piston to move away from the base and decrease the pressure of the gas
Physics
2 answers:
andrezito [222]3 years ago
6 0

Question:

Consider a sample of helium gas in a container fitted with a piston as pictured below. The piston is frictionless, but has a mass of 10.0 kg. How many of the following processes will cause the piston to move away from the base and decrease the pressure of the gas? Assume ideal behavior.

I. Heating the helium. II.

II. toRemoving some of the helium from the container.

III. Turning the container on its side.

IV. Decreasing the pressure outside the container.

a) 0

b) 1

c) 2

d) 3

e) 4

Answer:

Only one process will cause the piston to move which is

i) Heating the helium

Explanation:

When helium is heated it becomes less dense or lighter. Heating the helium will cause an increase in volume which will make the piston to move away from the base. When the volume finishes increasing, the piston will stop moving which in turn will make the forces on both sides of the piston balanced, so the pressure inside will balance the weight of the piston and that of the atmosphere. From that we can see that there has been a pressure change as a result of heating.

aev [14]3 years ago
3 0

Question:

Consider a sample of helium gas in a container fitted with a piston, as pictured below. The piston is frictionless, but has a mass of 10.0 kg. How many of the following processes will cause the piston to move away from the base and decrease the pressure of the gas? Assume ideal behavior.

I.

heating the helium

II.

removing some of the helium from the container

III.

turning the container on its side

IV.

decreasing the pressure outside the container

Answer:

Two of the following processes will cause the piston to move away from the base and decrease the pressure of the gas.

III and IV.

III.

turning the container on its side

IV.

decreasing the pressure outside the container

Explanation:

To answer the question, we will be required to analyze each option as follows

I.  

heating the helium

Here, assuming ideal behavior, according to Charles' law, at constant pressure the volume of a given mass of gas is directly proportional to its temperature, in  Kelvin.

Therefore, heating the helium will increase the volume of the gas and move up the piston to move away from the base. However the pressure will remain constant.

Only one condition is met

II.

removing some of the helium from the container

If the container is empty, the piston ill rest on the base of the container.

Does not meet the conditions.

III.

turning the container on its side

Here, the force of the piston on the helium gas due to grvity is removed, therefore the helium will expand and the pressure of the helium gas will be reduced as the force of the piston is no longer in effect, the volume  occupied by the gas increases, therefore the piston moves away from the base.

Both conditions are met.

IV.

decreasing the pressure outside the container

When the pressure outside the container is decreased the force due to atmospheric pressure is reduced and the helium will expand to assume a lesser equilibrium pressure while moving the piston away from the base.

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Answer:

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3 0
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stable equilibrium, if displaced from equilibrium, it experiences a net force or torque in a direction opposite to the direction of the displacement.

unstable equilibrium, if displaced it experiences a net force or torque in the same direction as the displacement from equilibrium. A system in unstable equilibrium accelerates away from its equilibrium position if displaced even slightly.

neutral equilibrium, is when an equilibrium is independent of displacements from its original position.

Have a good day, hope this helps

8 0
3 years ago
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jek_recluse [69]
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