Answer:
This link was diagram
Explanation:
https://doubtnut.app.link/FnsNC80Dccb
Answer:
1.8 m/s
Explanation:
momentum = mass × velocity
initial momentum = m1v1+m2v2
= 3×3 +2×0 = 9+0= 9 kg m/s
let combined velocity be V
HENCE
final momentum = total mass × velocity
= (3+2) × V = 5V
According to law of conservation of momentum
final momentum = initial momentum
5V = 9
V =9/5
V = 1.8 m/s
DNA is duplicated when two strands od DNA molecule complementary base pairs, the nucleotide has enough information needed to duplicate or if its Asexual meaning one parent dna will duplicate itself through the cells while sexual meaning two parents are involved you need both parents DNA to duplicate by the nucleotide.
Hello!
Work is equal to the change in KE or the negative change in PE. So if e field is directed vertically upward or in positive y direction and our charge is positive it’s going to move in direction of e field so then the work done by the e field is negative because it is losing potential energy the farther it moves upward away from field. Work=qed which is charge*e field*distance travelled.
Hope this helps! Any questions please ask! Thank you!!
Answer:
V(t) = (q0/C) * e^(−t/RC
)
Explanation:
If there were a battery in the circuit with EMF E , the equation for V(t) would be V(t)=E−(RC)(dV(t)/dt) . This differential equation is no longer homogeneous in V(t) (homogeneous means that if you multiply any solution by a constant it is still a solution). However, it can be solved simply by the substitution Vb(t)=V(t)−E . The effect of this substitution is to eliminate the E term and yield an equation for Vb(t) that is identical to the equation you solved for V(t) . If a battery is added, the initial condition is usually that the capacitor has zero charge at time t=0 . The solution under these conditions will look like V(t)=E(1−e−t/(RC)) . This solution implies that the voltage across the capacitor is zero at time t=0 (since the capacitor was uncharged then) and rises asymptotically to E (with the result that current essentially stops flowing through the circuit).