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Svetach [21]
3 years ago
13

Detailed research on comets indicates that they cannot be older than HOW MANY years.

Physics
2 answers:
Free_Kalibri [48]3 years ago
6 0
It would be, 1.000. Hope that helps :)
larisa86 [58]3 years ago
6 0

Answer:

100.000 or 10.000!!!!!!!! I tryed the other answer and it was wrong

Explanation:

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Weight = (mass) x (gravity)

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What law describes light
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A dogsled team is shown pulling a man on a sled. Below the picture is a free body diagram with 4 force vectors. The first vector
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Explanation:

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Read 2 more answers
A particle with charge 7.76×10^(−8)C is moving in a region where there is a uniform 0.700 T magnetic field in the +x-direction.
kodGreya [7K]

Answer:

The  z-component of the force is  \= F_z  =  0.00141 \ N    

Explanation:

From the question we are told that

          The charge on the particle is q =  7.76 *0^{-8} \  C    

           The magnitude of the magnetic field is  B =  0.700\r i \ T

            The  velocity of the particle toward the x-direction is  v_x  =  -1.68*10^{4}\r  i  \ m/s

           The  velocity of the particle toward the y-direction is

v_y  =  -2.61*10^{4}\ \r j  \ m/s

           The  velocity of the particle toward the z-direction is

v_y  =  -5.85*10^{4}\ \r k  \ m/s

Generally the force on this particle is mathematically represented as

          \= F  =  q (\= v   X  \= B )

So  we have    

          \= F  =  q ( v_x \r  i + v_y \r  j  +  v_z \r k  )  \ \ X \ (  \= B i)

         \= F  = q (v_y B(-\r  k) + v_z B\r j)      

  substituting values

       \= F  = (7.7 *10^{-8})([ (-2.61*10^{4}) (0.700)](-\r  z) + [(5.58*10^{4}) (0.700)]\r y)    

      \= F=  0.00303\ \r j +0.00141\ \r k                  

So the z-component of the force is  \= F_z  =  0.00141 \ N    

Note :  The  cross-multiplication template of unit vectors is  shown on the first uploaded image  ( From Wikibooks ).

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3 years ago
What kind of star gives rise to a type i supernova?
larisa86 [58]

a. It occures in binary systems where one of them is a whitedwarf

3 0
3 years ago
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