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Svetach [21]
3 years ago
13

Detailed research on comets indicates that they cannot be older than HOW MANY years.

Physics
2 answers:
Free_Kalibri [48]3 years ago
6 0
It would be, 1.000. Hope that helps :)
larisa86 [58]3 years ago
6 0

Answer:

100.000 or 10.000!!!!!!!! I tryed the other answer and it was wrong

Explanation:

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Write a rule for the sequence. 3, -3, -9, -15. A. Start with 3 and add -6 repeatedly B. Start with -6 and add 3 repeatedly C. St
faust18 [17]

Substract two consecutive terms of the sequence to see if there is a common difference:

\begin{gathered} (-3)-(3)=-3-3=-6 \\ (-9)-(-3)=-9+3=-6 \\ (-15)-(-9)=-15+9=-6 \end{gathered}

As we can see, there is a common difference of -6.

Then, if a number of the sequence is given, the next one can be found by adding -6 (which is the same as subtracting 6).

Notice that the first term of the sequence is 3.

Then, the rule for the sequence is to start with 3 and add -6 repeatedly.

Therefore, the correct choice is option A) Start with 3 and add -6 repeatedly.

7 0
2 years ago
5. Describe the shape of the waveform in the secondary coil for a sine, square and triangle wave in the primary coil. How does t
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Answer:

When primary coil is exited by sin wave,this will result in sin wave in secondary coil as well.According to law,flux induced in the secondary coil will have same waveform as in the primary coil.

5 0
4 years ago
Explain how you can improve the accuracy of a measurement. <br>​
yKpoI14uk [10]
You use more significant figures. 5 sigfigs (1.0985) is more accurate than 2 sigfigs (1.0)
8 0
2 years ago
Read 2 more answers
Which statement describes the relationship between bond strength and the melting and boiling points of a substance? A. As the fo
icang [17]

Answer:

a

Explanation:

4 0
3 years ago
The space shuttle usually orbited Earth at altitudes of around 300.0 km. 1) Determine the time for one orbit of the shuttle abou
777dan777 [17]

Answer:

Explanation:

distance of shuttle from centre of the earth = radius of the orbit

= 6300 + 300 = 6600 km

= 6600 x 10³

Formula of time period of the satellite

T = 2π R /v₀ , v₀ is orbital velocity

v₀ = √gR , ( if height  is small with respect to radius )

T = 2π R /√gR

= 2π√ R /√g

= 2 x 3.14 x √ 6600 x 10³ / √9.8

= 2 x 3.14 x 256.9 x 10 / 3.13

= 5154.41 s

= 5154.41 / 60 minutes

= 85.91 m

85.9 minutes.

2 ) No of sunrise per day = no of rotation per day

= 24 x 60 / 85.9

= 16.76

or 17 sunrises.

3 0
4 years ago
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