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4 years ago

What is the wave speed of a wave that has a frequency of 100Hz and a wavelength of .30m

Physics

1 answer:

GrogVix [38]4 years ago

8 0

Here is your answer

We know that

Velocity = Frequency × Wavelength

Here,

Frequency = 100Hz

Wavelength= .30m

So,

Velocity= 100× 0.30 m/s

v= 30 m/s

HOPE IT IS USEFUL

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When was the first airplane made?

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The first ariplanr was made December 17, 1903

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4 years ago

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A typical rechargeable deep-cycle battery for an electric trolling motor (fishing boat) delivers 10A of current at a voltage of

Oksi-84 [34.3K]

Answer:

a) 360 kQ

b) 4.32 MJ

c) 1200 W-h

Explanation:

a) The definition of the current is.

$I= \frac{Q}{t}$

having a count that 10 hours = 36.000 s

$Q = I*t$

$Q = 36000*10 = 360.000 [Q]$

b) The definition of the Energy in power terms is.

$E = \int\limits^{t}_{0} {P} \, dt$

and the definition of power is:

$P = V*I = 12 * 10 = 120 [W]$

replacing in the energy formula.

$E = \int\limits^{36.000}_{0} {120} \, dt$

solving the integral, have into account that t is in seconds.

$E=P*t=120*36000=4.320.000=4.32 [MJ]$

c) The energy in W-h, we can find it multiplying power by hours

$E = P*t =120*10 = 1200 W-h$ .

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3 years ago

A heat engine accepts 200,000 Btu of heat from a source at 1500 R and rejects 100,000 Btu of heat to a sink at 600 R. Calculate

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To solve the problem it is necessary to apply the concepts related to the conservation of energy through the heat transferred and the work done, as well as through the calculation of entropy due to heat and temperatra.

By definition we know that the change in entropy is given by

$\Delta S = \frac{Q}{T}$

Where,

Q = Heat transfer

T = Temperature

On the other hand we know that by conserving energy the work done in a system is equal to the change in heat transferred, that is

$W = Q_{source}-Q_{sink}$

According to the data given we have to,

$Q_{source} = 200000Btu$

$T_{source} = 1500R$

$Q_{sink} = 100000Btu$

$T_{sink} = 600R$

PART A) The total change in entropy, would be given by the changes that exist in the source and sink, that is

$\Delta S_{sink} = \frac{Q_{sink}}{T_{sink}}$

$\Delta S_{sink} = \frac{100000}{600}$

$\Delta S_{sink} = 166.67Btu/R$

On the other hand,

$\Delta S_{source} = \frac{Q_{source}}{T_{source}}$

$\Delta S_{source} = \frac{-200000}{1500}$

$\Delta S_{source} = -133.33Btu/R$

The total change of entropy would be,

$S = \Delta S_{source}+\Delta S_{sink}$

$S = -133.33+166.67$

$S = 33.34Btu/R$

Since $S\neq 0$ the heat engine is not reversible.

PART B)

Work done by heat engine is given by

$W=Q_{source}-Q_{sink}$

$W = 200000-100000$

$W = 100000 Btu$

Therefore the work in the system is 100000Btu

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3 years ago

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Answer: A) <u>Either source or listener must be moving.</u>

Explanation:

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3 years ago

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padilas [110]

Answer: 9.8N

Explanation: The velocity of a sound wave (v), tension on the string (T) and mass per unit length (u) are all related by the formulae below

T = v² * u

Where T is tension in Newton (N), v is velocity of sound waves in meter per seconds (m/s) and u is mass per unit length in kilogram per meter (kg/m)

u = mass of chord / length of chord

u = 0.44/ 8.1

u = 0.1 kg/m

Velocity of sound waves (v) =length of chord / time taken for wave to travel

v = 8.1 / 0.82 = 9.9m/s

Tension is calculated below using the formula

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T = (9.9)² x 0.1

T= 9.8N

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