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Brilliant_brown [7]
3 years ago
9

Based on Newton’s First Law, what would you expect to happen to a block that is pushed across ice and begins moving (You may ass

ume there is no friction for this scenario? What would be necessary to cause the block to stop moving?
Physics
2 answers:
allsm [11]3 years ago
5 0
I think an unbalanced force too.

Montano1993 [528]3 years ago
3 0
An unbalanced force.
Newton's first law states that an object in motion will stay in motion until a unbalanced force acts upon it.
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An object weighs 32 newtons. What is its mass if a gravitometer indicates that g = 8.25 m/s?
Elan Coil [88]

Explanation:

weight=mass×g

32=mass×8.25

mass=

\frac{128}{33}  = 3.878kg

8 0
3 years ago
Explain what major mistake producers made when editing the battle scenes for the movie Star Wars
Artyom0805 [142]

Answer: Air

Explanation:

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4 0
3 years ago
What is the square root of 25x10^12
kirill115 [55]

\sqrt{25 \times 10^{12} }

In order to find it's square root, we could make it into two square roots.

\sqrt{25 \times 10^{12} } = \sqrt{25} \times \sqrt{10^{12}}

Let us find the square roots of both radicals seprately.

\sqrt{25} =\sqrt{5*5}=5

Each  pair  of a number inside square root gives a number out .

\sqrt{10^{12}} = \sqrt{10*10*10*10*10*10*10*10*10*10*10*10}   \ \ ( \ makes \ 6 \ pairs \ of \ 10 )

\sqrt{10*10*10*10*10*10*10*10*10*10*10*10} = 10*10*10*10*10*10

= 10^6.

Therefore,

\sqrt{25 \times 10^{12} }=\sqrt{25} \times \sqrt{10^{12}}={5 \times 10^6}

\sqrt{25 \times 10^{12} } = {5 \times 10^6}

7 0
3 years ago
What is the electric potential 12 cm away from a charge of –5.2 × 10^–6C?
MAXImum [283]
The equation for electric potential of a point charge is:

V=(k*q)/r where k=9*10^11 N m²/C², q is the charge and r is the distance from the charge to the point in which we are calculating the potential.

q=-5.2*10^-6 C
r=12 cm = 0.12 m

Now we plug in the numbers and get:

V=-3.9*10^5 Volts, so the correct answer is the second one. 
8 0
3 years ago
Match the descriptions to the feature,
Marysya12 [62]

Answer:

Vertex: Point where the principal axis and mirror meet

Focal point: Point we are reflected light converges or appears to diverge

Focal length: distance from the center of a mirror to the focal point

Principal axis: line that runs to the center of curvature to a mirror

Center of curvature: sensor of spherical mirror from which a curved mirror was cut

Explanation:

Just did the assignment on Edge.

4 0
3 years ago
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