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KatRina [158]
3 years ago
7

Whats the answer to this

Chemistry
1 answer:
Natasha2012 [34]3 years ago
3 0
I think the answer you have selected is right, I'm not sure tho
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An element is a pure substance in which there are how many kinds of atoms?
Ostrovityanka [42]

Answer:

One

Explanation:

An element is a pure substance in which there are only one kind of atom. Elements are distinct substances that cannot be split up into simpler substances.

Such substances consists of only one kind of atom. There are over a hundred known elements to date.

Generally, as a pure substance, the composition of an element is definite and they are homogenous in all parts.

8 0
3 years ago
How many moles of carbon are in the sample?
jeka94

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5 0
3 years ago
Rank the following elements in order of decreasing atomic radius (1 is biggest, 5 is smallest)
AlexFokin [52]

There are various kind of elements that are present in periodic table. Some elements are harmful, some are radioactive, some are noble gases. The atomic radius in decreasing order is Bi>Sb>As>N>O.

<h3>What is periodic table?</h3>

Periodic table is a table in which we find elements with properties like metals, non metals, metalloids and radioactive element arranges in increasing atomic number.

Along the period, the size of elements decreases. Down the group the size of elements increases. The atomic radius in decreasing order is Bi>Sb>As>N>O.

Therefore, atomic radius in decreasing order is Bi>Sb>As>N>O.

Learn more about periodic table, here:

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3 0
1 year ago
Enter a range of values for x, 2x+10, 14 ​
PIT_PIT [208]

Answer:

62 degrees and 15.

Explanation:

3 0
3 years ago
calculate the heat required in joules to convert 18.0 grams of water ice at a temperature of -20 c to liquid water at the normal
KIM [24]

Answer:

Explanation:

Heat required to convert ice to ice at 0⁰C

= mass x specific heat x rise in temperature

= 18 x 2.09 x 20

= 752.4 J .

heat required to convert ice at 0⁰C to water at 0⁰C

mass x latent heat of fusion

= 18 x 336

= 6048 J

Heat required to increase the temperature of water to 100⁰C

= 18 x 4.2 x 100

= 7560 J

Total heat required

7560 + 6048 + 752.4

= 14360.4 J

7 0
3 years ago
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