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Strike441 [17]
3 years ago
12

Which subshell is represented by the lanthanides family

Chemistry
1 answer:
balu736 [363]3 years ago
8 0
Subshell f is represneted
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Differentiate between ideal and non - ideal solutions.<br><img src="https://tex.z-dn.net/?f=%20%5C%5C%20" id="TexFormula1" title
nordsb [41]

Answer:

Ideal Solution: An ideal solution is a solution where interactions between molecules are identical between all the molecules in the solution. Non ideal Solution: A non ideal solution is a solution that has differences in the interactions between molecules of different components in the solution.

Explanation:

3 0
2 years ago
Read 2 more answers
Why is BrCl5 nonpolar when it's Asymmetrical? Aren't symmetrical molecules suppposed to be polar?
Svet_ta [14]
Although there exists a dipole moment in the molecule, I guess its nonpolar because the dipole is very small as the electronegativity difference between the Br and Cl is very low and so it can be neglected.
8 0
4 years ago
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Determine the pH of a 0.048 M hypochlorous acid (HClO) solution. Hypochlorous acid is a weak acid (Ka = 4.0 ✕ 10−8 M).
storchak [24]

pH of 0.048 M HClO is 4.35.

<u>Explanation:</u>

HClO is a weak acid and it is dissociated as,

HClO ⇄ H⁺ + ClO⁻

We can write the equilibrium expression as,

Ka = $\frac{[H^{+}] [ClO^{-}]  }{[HClO]}

Ka = 4.0 × 10⁻⁸ M

4.0 × 10⁻⁸ M = $\frac{x \times x }{0.048}

Now we can find x by rewriting the equation as,

x² =  4.0 × 10⁻⁸ × 0.048

   = 1.92 × 10⁻⁹

Taking sqrt on both sides, we will get,

x = [H⁺] = 4.38 × 10⁻⁵

pH = -log₁₀[H⁺]

     = - log₁₀[ 4.38 × 10⁻⁵]

   = 4.35

8 0
3 years ago
How many atoms are contained in 12.5 grams of silver? A. 6.97 × 1022 atoms B. 7.52 × 1024 atoms C. 0.116 atoms D. 1.92 × 10–25 a
satela [25.4K]
M(Ag)=12.5 g
Nₐ=6.022*10²³ mol⁻¹

n(Ag)=m(Ag)/M(Ag)

N=n(Ag)*Nₐ

N=Nₐm(Ag)/M(Ag)

N=6.022*10²³mol⁻¹*12.5g/107.868g/mol=6.97*10²²


A. 6.97 × 10²² atoms

7 0
3 years ago
How many moles are in .5g of sodium bromide?
3241004551 [841]

Answer: 4.86 x 10⁻³ mole.

Explanation:

  • The number of moles can be calculated using the relation; n = mass / molar mass.
  • n is the number of moles, mass is the mass of the substance in g (m = 0.5 g), and molar mass of NaBr = 102.894 g/mole.
  • n = mass / molar mass = (0.5 g) / (102.894 g/mole) = 4.86 x 10⁻³ mole.
8 0
3 years ago
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