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3 years ago

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How did admitting Mendeleev deal with elements that had not yet been discovered

1 answer:

Len [333]3 years ago

7 0

Mendeleev organized his table by atomic mass, rather than atomic radius. He was able to extrapolate where certain undiscovered elements should be on the table based on that.

For example, he said that since Calcium has mass of 40g and Titanium has a mass of 48 g, there must be some element between them with atomic mass of 44 g. That was later discovers to be scandium.

Hope this helps

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I need help with stoichometrey

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3 years ago

The Charles Zeppelin, a fictional airship, is filled with 2.16 x 105 liters of hydrogen gas (H2). On the ground, the airship’s t

Dmitry [639]

Answer:

V2 = 3.11 x 105 liters

Explanation:

Initial Volume, V1 = 2.16 x 105 liters

Initial Temperature, T1 = 295 K

Final Temperature, T2 = 425 K

Final Volume, V2 = ?

These quantities are related by charle's law and the equation of the law is given as;

V1 / T1 = V2 / T2

V2 = T2 * V1 / T1

V2 = 425 * 2.16 x 105 / 295

V2 = 3.11 x 105 liters

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3 years ago

olchik [2.2K]

Answer:

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Translucent → b.some light travels through the material and the image cannot be seen clearly

Transparent → c.all light travels through the material and the image can be seen clearly

Explanation:

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7 0

3 years ago

Read 2 more answers

Where does the force that helps sediment become sedimentary rock come from?

Sidana [21]

Answer:

I think it's compaction I'm not sure

5 0

2 years ago

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A critical reaction in the production of energy in biological systems is the hydrolysis of adenosine triphosphate (ATP) to adeno

Archy [21]

Answer:

ΔG° of reaction = -47.3 x $10^{3}$ J/mol

Explanation:

As we can see, we have been a particular reaction and Energy values as well.

ΔG° of reaction = -30.5 kJ/mol

Temperature = 37°C.

And we have to calculat the ΔG° of reaction in the biological cell which contains ATP, ADP and HPO4-2:

The first step is to calculate the equilibrium constant for the reaction:

Equilibrium Constant K = $\frac{[HPO4-2] x [ADP]}{ATP}$

And we have values given for these quantities in the biological cell:

[HP04-2] = 2.1 x $10^{-3}$ M

[ATP] = 1.2 x $10^{-2}$ M

[ADP] = 8.4 x $10^{-3}$ M

Let's plug in these values in the above equation for equilibrium constant:

K = $\frac{[2.1x10^{-3}] x [8.4x10^{-3}] }{[1.2 x 10^{-2}] }$

K = 1.47 x $10^{-3}$ M

Now, we have to calculate the ΔG° of reaction for the biological cell:

But first we have to convert the temperature in Kelvin scale.

Temp = 37°C

Temp = 37 + 273

Temp = 310 K

ΔG° of reaction = (-30.5 $10^{3}$ ) + (8.314)x (310K)xln(0.00147)

Where 8.314 = value of Gas Constant

ΔG° of reaction = (-30.5 x $10^{3}$ ) + (-16810.68)

ΔG° of reaction = -47.3 x $10^{3}$ J/mol

5 0

3 years ago