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Paraphin [41]
4 years ago
15

You're supposed to simplify these, but for the last one, isn't it simplified enough?

Mathematics
1 answer:
Nookie1986 [14]4 years ago
4 0
Yes. It is simplified all of the way.
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I need help with math please
zvonat [6]

Answer:

Rational and integer i.e option A and C

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3 years ago
How did Ramses ll use the military to improve the Egyptian empire?
Travka [436]

True Answer

A. He used military to retake old egyptian territory.

5 0
3 years ago
A juice factory offers its juice in both bottles and cans. A class of students on a field trip decides to compare the numbers of
Verizon [17]

Answer: 50 cases per minute

Step-by-step explanation:

1. Select one of the points on the graph. Let's use (2, 100) in this case.

2. Divide the number of cases (y) by the amount of minutes (x) This means the equation would be 100 ÷ 2.

3. Since 100 cases ÷ 2 minutes = 50 cases per minute, that means that is unit rate, which can be expressed by y = 50x or f(x) = 50x.

7 0
3 years ago
Read 2 more answers
Find all points on the x-axis that are 14 units from the point (4, -7).
BaLLatris [955]

Answer:

The points are: (16.12,0),(-8.12,0).

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

Distance between two points:

Suppose we have two points, (x_1,y_1) and (x_2,y_2). The distance between them is given by:

D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Find all points on the x-axis that are 14 units from the point (4, -7).

Being on the x-axis mean that they have y-coordinate equal to 0, so the point is (x,0).

The distance is 14. So

\sqrt{(x-4)^2+(0-(-7))^2} = 14

\sqrt{x^2 - 8x + 16 + 49} = 14

\sqrt{x^2 - 8x + 65} = 14

(\sqrt{x^2 - 8x + 65})^2 = 14^2

x^2 - 8x + 65 - 196 = 0

x^2 - 8x - 131 = 0

So a = 1, b = -8, c = -131

\bigtriangleup = (-8)^{2} - 4(1)(-131) = 588

x_{1} = \frac{-(-8) + \sqrt{588}}{2} = 16.12

x_{1} = \frac{-(-8) - \sqrt{588}}{2} = -8.12

The points are: (16.12,0),(-8.12,0).

4 0
3 years ago
Question 10 The hypotenuse of a right triangle is I m longer than the longer leg. The other leg is 7 m shorter than the longer l
bonufazy [111]

Answer:

5, 12, 13

Step-by-step explanation:

let x be the longer leg then x + 1 is the hypotenuse and x - 7 the shorter leg

Using Pythagoras' identity in the right triangle

x² + (x - 7)² = (x + 1)² ← expand using FOIL

x² + x² - 14x + 49 = x² + 2x + 1

2x² - 14x + 49 = x² + 2x + 1 ( subtract x² + 2x + 1 from both sides )

x² - 16x + 48 = 0 ← in standard form

(x - 4)(x - 12) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 4 = 0 ⇒ x = 4

x - 12 = 0 ⇒ x = 12

x = 4 , then x - 7 = 4 - 7 = - 3 ← not possible

x = 12, then x - 7 = 12 - 7 = 5 and x + 1 = 12 + 1 = 13

The lengths of the 3 sides are

longer leg = 12 m , shorter leg = 5 m and hypotenuse = 13 m

5 0
3 years ago
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