Given two questions:
<span>1) If a car passes a pedestrian, a change in pitch is ______________.
The answer is the change in pitch is perceived by the pedestrian since he is the one in a relatively constant position compared to the car passing.
2) </span><span>In the Doppler Effect lab, which statement best describes what you demonstrated about speed and pitch?
The answer is 'speed and direction affect pitch'.</span>
Answer is B.
As the diaphragm contracts and flattens, it increases the volume of the thorax where the lungs are located. This results in a decrease in pressure (Boyle’s Law, if you know it) that creates a pressure gradient from outside to inside. This is what causes air to move into the lungs.
<em>answer:</em><em> </em><em>option </em><em>d </em><em>(</em><em>2</em><em>×</em><em>m</em><em>o</em><em>l</em><em>a</em><em>r</em><em> </em><em>mass </em><em>of </em><em>H </em><em>+</em><em>2</em><em>×</em><em>m</em><em>o</em><em>l</em><em>a</em><em>r</em><em> </em><em>mass </em><em>of </em><em>O</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>
Answer:
Explanation:
moles of acetic acid = 500 x 10⁻³ x .1 M
= 5 X 10⁻³ M
.005 M
Moles of NaOH = .1 M
Moles of sodium acetate formed = .005 M
Moles of NaOH left = .095 M
pOH = 4.8 + log .005 / .095
= 4.8 -1.27875
= 3.52125
pH = 14 - 3.52125
= 10.48
