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suter [353]
3 years ago
9

A rock sample contains 4.5g of Potassium-40 and 31.5g of its daughter isotope (Argon-40). How old is the rock sample if Potassiu

m-40 has a half-life of 1.3 billion years?
Chemistry
1 answer:
brilliants [131]3 years ago
8 0
<span>There is a starting mass of 36g of Potassium-40. After 1.3 billion years, there would be 18g of Argon-40. After 2.6 billion years, half of the remaining Potassium-40 would have decayed, leaving 9g of Potassium-40 and giving us 27g of Argon-40. Following this pattern, we see that three half-lives, or 3.9 billion years, have passed. The age of the rock sample is 3.9 billion years.</span>
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See explanation.

Explanation:

Hello,

In this case, we could have two possible solutions:

A) If you are asking for the molar mass, you should use the atomic mass of each element forming the compound, that is copper, sulfur and four times oxygen, so you can compute it as shown below:

M_{CuSO_4}=m_{Cu}+m_{S}+4*m_{O}=63.546 g/mol+32.00g/mol+4*16.00g/mol\\\\M_{CuSO_4}=159.546g/mol

That is the mass of copper (II) sulfate contained in 1 mol of substance.

B) On the other hand, if you need to compute the moles, forming a 1.0-M solution of copper (II) sulfate, you need the volume of the solution in litres as an additional data considering the formula of molarity:

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So you can solve for the moles of the solute:

n_{solute}=M*V_{solution}

Nonetheless, we do not know the volume of the solution, so the moles of copper (II) sulfate could not be determined. Anyway, for an assumed volume of 1.5 L of solution, we could obtain:

n_{solute}=1mol/L*1.5L=1.5mol

But this is just a supposition.

Regards.

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