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suter [353]
3 years ago
9

A rock sample contains 4.5g of Potassium-40 and 31.5g of its daughter isotope (Argon-40). How old is the rock sample if Potassiu

m-40 has a half-life of 1.3 billion years?
Chemistry
1 answer:
brilliants [131]3 years ago
8 0
<span>There is a starting mass of 36g of Potassium-40. After 1.3 billion years, there would be 18g of Argon-40. After 2.6 billion years, half of the remaining Potassium-40 would have decayed, leaving 9g of Potassium-40 and giving us 27g of Argon-40. Following this pattern, we see that three half-lives, or 3.9 billion years, have passed. The age of the rock sample is 3.9 billion years.</span>
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Answer:

13.9g of CuSO4•5H2O

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

CuSO4•5H2O → CuSO4 + 5H2O

Next, we shall determine the mass of CuSO4•5H2O heated and the mass of H2O produced from the balanced equation.

This is illustrated below

Molar mass of CuSO4• 5H2O = 63.5 + 32 + (16x4) + 5(2x1 + 16)

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Mass of CuSO4•5H2O from the balanced equation = 1 x 249.5 = 249.5g

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Mass of H2O from the balanced equation = 5 x 18 = 90g

From the balanced equation above,

249.5g of CuSO4•5H2O produced 90g of H2O.

Now, we can determine the mass of CuSO4•5H2O needed to produce 5g of H2O. This can be achieved as shown below:

From the balanced equation above,

249.5g of CuSO4•5H2O produced 90g of H2O.

Therefore, Xg of CuSO4•5H2O will produce 5g of H2O i.e

Xg of CuSO4•5H2O = (249.5 x 5)/90

Xg of CuSO4•5H2O = 13.9g

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