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givi [52]
2 years ago
9

8 l of water at 19 ∘c are mixed with 1.1 l of water at 47 ∘c in an insulated container. what is the final temperature of the sys

tem? express your answer in ∘c
Chemistry
1 answer:
stepladder [879]2 years ago
5 0
1692.9 is the answer


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What is the enthalpy of combustion when 1 mol C6H6(g) completely reacts with oxygen? 2C6H6(g) 15O2(g) mc001-1. Jpg 12CO2(g) 6H2O
Andrei [34K]

The enthalpy of combustion of 1 mole of benzene is 3169 kJ/mol .

The first step in answering this question is to obtain the balanced thermochemical equation of the reaction. The thermochemical equation shows the amount of heat lost or gained.

The thermochemical equation for the combustion of benzene is;

2 C6H6(l) + 15 O2(g) → 12 CO2(g) + 6 H2O(g) ΔrH° = -3169 kJ/mol

We can see that 1 mole of benzene releases about 3169 kJ/mol of heat.

Learn more: brainly.com/question/13164491

8 0
2 years ago
If the half life of a radioactive isotope is 5000 years, how much of the radioactive isotope in a specimen will be left after 10
marissa [1.9K]
Half life is the time taken by a radioactive isotope to decay by half its original mass. In this case, the halflife of the radioactive isotope is 5000 years. 
Initially the mass is 100 %; thus the mass that will be left will be given by;
New mass = Original mass × (1/2)^n where n is the number of half lives; 
  n = 10000/5000 = 2
New mass = 100% ×(1/2)^2
                 = 100 % × 1/4 
                 = 25%
Therefore; the mass left after 10000 years is 25% or 1/4 of the original mass.
5 0
3 years ago
Which of the following would remain a liquid longer as temperature continues to drop?
viktelen [127]

I just took a test with this question and got the answer wrong for saying ethane. The correct answer is propane.

3 0
2 years ago
Read 2 more answers
The empirical formula of an organic compound is C2H4O. The molecular mass of the compound is 176g/mol.
Brrunno [24]

Answer:

The molecular formula of the compound is C_{8}H_{16}O_{4}. The molecular formula is obtained by the following expression shown below

\textrm{Molecular formula }= n\times \textrm{Empirical formula}

Explanation:

Given molecular mass of the compound is 176 g/mol

Given empirical formula is  C_{2}H_{4}O

Atomic mass of carbon, hydrogen and oxygen are 12 u , 1 u and 16 u respectively.

Empirical formula mass of the compound = \left ( 2\times12+4+16 \right ) \textrm{ u} = 44 \textrm{ g/mol}

n = \displaystyle \frac{\textrm{Molecular formula mass}}{\textrm{Empirical formula mass}} \\n = \displaystyle \frac{176}{44} = 4

\textrm{Molecular formula }= n\times \textrm{Empirical formula}

Molecular formula = 4 \times C_{2}H_{4}O

Molecular formula is C_{8}H_{16}O_{4}

6 0
2 years ago
How many neon atoms are contained in (7.27x10^2) grams of neon?
statuscvo [17]

Answer: 2.19x10^25 atoms

Explanation:

Molar Mass of Neon = 20g/mol

1mole(20g) of Neon contains 6.02x10^23 atoms.

Therefore, 7.27x10^2g of Neon will contain x atoms i.e

X atoms = (7.27x10^2x6.02x10^23)/20 = 2.19x10^25 atoms

4 0
2 years ago
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