Answer:
D = 28.2g
Explanation:
Initial temperature of metal (T1) = 155°C
Initial Temperature of calorimeter (T2) = 18.7°C
Final temperature of solution (T3) = 26.4°C
Specific heat capacity of water (C2) = 4.184J/g°C
Specific heat capacity of metal (C1) = 0.444J/g°C
Volume of water = 50.0mL
Assuming no heat loss
Heat energy lost by metal = heat energy gain by water + calorimeter
Heat energy (Q) = MC∇T
M = mass
C = specific heat capacity
∇T = change in temperature
Mass of metal = M1
Mass of water = M2
Density = mass / volume
Mass = density * volume
Density of water = 1g/mL
Mass(M2) = 1 * 50
Mass = 50g
Heat loss by the metal = heat gain by water + calorimeter
M1C1(T1 - T3) = M2C2(T3 - T2)
M1 * 0.444 * (155 - 26.4) = 50 * 4.184 * (26.4 - 18.7)
0.444M1 * 128.6 = 209.2 * 7.7
57.0984M1 = 1610.84
M1 = 1610.84 / 57.0984
M1 = 28.21g
The mass of the metal is 28.21g
Answer:
0.3097 moles of an nonionizing solute would need to be added.
Explanation:
Molal elevation constant = 
Normal boiling point of ethanol = 
Boiling of solution =
Moles of nonionizing solute = n
Mass of ethanol (solvent) = 47.84 g
Elevation boiling point:
n = 0.3097 mol
0.3097 moles of an nonionizing solute would need to be added.
For neutralization of acid by a base (or vice versa), the equation should be used.
M₁V₁ = M₂V₂
where M's are the molarity and the Vs are the volume. Substituting the known values,
(0.150M)(25) = M₂(15 mL)
The value of M₂ from the equation is equal to 0.25M. Thus, the concentration of the acid is 0.25M.
The title explains what the graph topic will be or what the graph will be about.If it was off topic from what the graph shows,that will just be confusing.
<h3><u>Answer</u>;</h3>
= 1.38 moles
<h3><u>Explanation</u>;</h3>
Using the equation;
PV = nRT , where P is the pressure,. V is the volume, n is the number of moles and T is the temperature and R is the gas constant, 0.08206 L. atm. mol−1.
P= 331 000Pa or 3.267 atm T= 197.4 +273 = 470.4, V = 16.3 L
Therefore;
n = PV/RT
= (3.267 × 16.3)/(470.4 × 0.08206)
= 1.3796 moles
≈ 1.38 moles
