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Mariana [72]
4 years ago
14

A decrease in the amount of a gas in a container may mean a(n) __________. increase in pressure increase in volume decrease in p

ressure decrease in volume
Chemistry
1 answer:
enot [183]4 years ago
5 0
A decrease in the amount of gas in a container will mean a decrease in pressure.
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You have 263 mL of liquid mercury, what is the mass of mercury that you have?
Gelneren [198K]

Answer:3,550.5 g

Explanation:

Mass= density×volume

Mass= 13.5g/m.l×263ml

Mass=3,550.5 g

Please add me the brainleist!!!!!!!!

7 0
3 years ago
The point in a titration when the added amount of standard reagent is equal to the amount of analyte being titrated.
creativ13 [48]
That point is called as EQUILIBRIUM, and then you have to note that value to compare with others
8 0
3 years ago
What happens to iron when it melts?
iren [92.7K]

Answer:

B. It undergoes a physical change.

Explanation:

Hello there!

In this case, since we know that chemical changes lead to the formation of new atoms and/or compounds due to the bonds rearrangement of the initial substances and the physical changes occur without changing the composition of the initial substances, we can infer that, since melting is a process that changes the phase of matter from solid to liquid without changing the identity of the initial substance, the answer to this question would be B. It undergoes a physical change. because the other options describe chemical changes.

Best regards!

5 0
2 years ago
Read 2 more answers
The great French chemist Antoine Lavoisier discovered the Law of Conservation of Mass in part by doing a famous experiment in 17
yawa3891 [41]

Answer:

a. 2 HgO(s) ⇒ 2 Hg(l) + O₂(g)

b. 0.957 g

Explanation:

Step 1: Write the balanced equation

2 HgO(s) ⇒ 2 Hg(l) + O₂(g)

Step 2: Convert 130.0 °C to Kelvin

We will use the following expression.

K = °C + 273.15

K = 130.0°C + 273.15

K = 403.2 K

Step 3: Calculate the moles of O₂

We will use the ideal gas equation.

P × V = n × R × T

n = P × V/R × T

n = 1 atm × 0.0730 L/0.0821 atm.L/mol.K × 403.2 K

n = 2.21 × 10⁻³ mol

Step 4: Calculate the moles of HgO that produced 2.21 × 10⁻³ moles of O₂

The molar ratio of HgO to O₂ is 2:1. The moles of HgO required are 2/1 × 2.21 × 10⁻³ mol = 4.42 × 10⁻³ mol.

Step 5: Calculate the mass corresponding to 4.42 × 10⁻³ moles of HgO

The molar mass of HgO is 216.59 g/mol.

4.42 × 10⁻³ mol × 216.59 g/mol = 0.957 g

5 0
3 years ago
Can someone help on this?
AlexFokin [52]

Answer:

Igneous=B

Sedimentary=C

Metamorphic=A

Weathering is when=B

If sedimentary rock.....=C

8 0
4 years ago
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