a cylinder has a density of 3.75g/cm3. if it has a mass of 12.1 g and a diameter of 8.22 cm, what is its height?
1 answer:
Given that
Cylinder density = 3.75 g/ cm^3
Mass of cylinder = 12.1 g
Diameter = 8.22 cm
Radius, r = diameter /2 = 8.22 /2 cm = 4.11 cm
Now calculate the volume as follows:
Volume = mass / density
= 12.1 g/ 3.75 g/ cm^3
= 3.23 cm^3
Now with the use of volume of cylinder calculate the height as follows:
Volume of cylinder = πr^2h
3.23 cm^3 = 3.14 * (4.11 cm)^2 *h
h = 3.23 cm^3 / 3.14 * (4.11 cm)^2
=0.061 cm
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1.43 × 10⁻²⁰ mol Li
<h3>General Formulas and Concepts:</h3><u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
- Left to Right
<u>Chemistry</u>
<u>Atomic Structure</u>
- Using Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Step 1: Define</u>
8.63 × 10³ atoms Li
<u>Step 2: Identify Conversions</u>
Avogadro's Number
<u>Step 3: Convert</u>
- Set up:
- Multiply/Divide:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
1.43355 × 10⁻²⁰ mol Li ≈ 1.43 × 10⁻²⁰ mol Li