All categories

3 years ago

C2 H6 +02 equals CO2 + H2O what mass of water is produced from three moles of C2 H6?

Chemistry

1 answer:

yulyashka [42]3 years ago

8 0

Answer:

162g

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

2C2H6 + 7O2 —> 4CO2 + 6H2O

Next, we shall determine the number of mole of water, H2O produced by the reaction of 3 moles of C2H6.

This can be obtained as follow:

From the balanced equation above,

2 moles of C2H6 reacted to produce 6 moles of H2O.

Therefore, 3 moles of C2H6 will react to produce = (3 x 6)/2 = 9 moles of H2O.

Therefore, 9 moles of H2O is produced from the reaction.

Finally, we shall convert 9 moles of H2O to grams.

This can be done as shown below:

Molar mass of H2O = (2x1) + 16 = 18g/mol

Mole of H2O = 9 moles

Mass of H2O =..?

Mole = mass / molar mass

9 = mass of H2O /18

Cross multiply

Mass of H2O = 9 x 18

Mass of H2O = 162g

Therefore, 162g of H2O were produced from 3 moles of C2H6.

You might be interested in

What force must act on a 150 kg mass to give it an acceleration of 30 m/s squared? F=ma

Helga [31]

Answer:

its 120

Explanation:

i did it :)

4 0

2 years ago

A 0.5438 g of a C.H.O. compound was combusted in air to make 1.039 g of CO2 and 0.6369 g H20. What is the empirical formula? Bal

goblinko [34]

Answer:

C₃H₅O₂

4C₃H₅O₂ + 13O₂ → 12CO₂ + 10H₂O

Explanation:

The reaction can be expressed as:

CₓHₓOₓ + nO₂ → CO₂ + H₂O

Under the assumption that there was a total combustion, all of the carbon in the reactant was combusted into CO₂, so the mass of C contained in the C.H.O. compound is the same mass of C contained in 1.039 g of CO₂:

$1.039gCO_{2}*\frac{1molCO_{2}}{44gCO_{2}} *\frac{1molC}{1molCO_{2}} *\frac{12gC}{1molC} =0.2834gC$

All of the hydrogens atoms in the compound ended up becoming H₂O, so the mass of H contained in the C.H.O. compound is the same mass of H contained in 0.6369 g of H₂O:

$0.6369g*\frac{1molH_{2}O}{18gH_{2}O} *\frac{1molH}{1molH_{2}O} *\frac{1gH}{1molH} =0.0354gH$

Because the compound is composed only by C, H and O, the mass of O in the compound can be calculated by substraction:

0.5438 g Compound - 0.2834 g C - 0.0354 g H = 0.2250 g O

In order to determine the empirical formula, we calculate the moles of each component:

mol C = 0.2834 g C ÷ 12 g/mol = 0.0236 mol C

mol H = 0.0354 g H ÷ 1 g/mol = 0.0354 mol H

mol O = 0.2250 g O ÷ 16 g/mol = 0.0141 mol O

Then we divide those values by the lowest one:

0.0236 mol C ÷ 0.0141 = 1.67

0.0354 mol H ÷ 0.0141 = 2.51

0.0141 mol O ÷ 0.0141 = 1

If we multiply those values by 2, we're left with the empirical formula C₃H₅O₂.

The reaction is:

4C₃H₅O₂ + 13O₂ → 12CO₂ + 10H₂O

8 0

2 years ago

What is the volume of 1.56 kg of a compound whose molar mass is 81.86 g/mole and whose density is 41.2 g/ml?

hjlf

Answer:

v = 37.9 ml

Explanation:

Given data:

Mass of compound = 1.56 kg

Density = 41.2 g/ml

Volume of compound = ?

Solution:

First of all we will convert the mass into g.

1.56 ×1000 = 1560 g

Formula:

D=m/v

D= density

m=mass

V=volume

v = m/d

v = 1560 g / 41.2 g/ml

v = 37.9 ml

7 0

2 years ago

Explain how lithium atom is positive charge

yulyashka [42]

Lithium is an element that has an electronic configuration of 2,1. So when forming bonds, it tries to release one of its electrons in the last shell to reach the octet state. Normally when atoms release electrons they get positive charge since the number of protons which bear positive charge, is higher than number of electrons which bear negative charge. So when reaching its octet state, lithium gains positive charge!

Hope this helps! Tbh am not good at explaining. If u have any doubts, ask me!

4 0

2 years ago

Give the name of the prefix and the quantity indicated by the following symbols that are used with SI base units.

Serhud [2]

Answer:

A. Centi, 10*-2

B. Deci, 0.1 or 10*-1

C. Giga, 10*9

D. Kilo, 10*3

E. Milli, 10*-3

F. Nano, 10*-9

G. Pico, 10*-12

H. Tera, 10*12

7 0

2 years ago