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nataly862011 [7]
3 years ago
9

C2 H6 +02 equals CO2 + H2O what mass of water is produced from three moles of C2 H6?

Chemistry
1 answer:
yulyashka [42]3 years ago
8 0

Answer:

162g

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

2C2H6 + 7O2 —> 4CO2 + 6H2O

Next, we shall determine the number of mole of water, H2O produced by the reaction of 3 moles of C2H6.

This can be obtained as follow:

From the balanced equation above,

2 moles of C2H6 reacted to produce 6 moles of H2O.

Therefore, 3 moles of C2H6 will react to produce = (3 x 6)/2 = 9 moles of H2O.

Therefore, 9 moles of H2O is produced from the reaction.

Finally, we shall convert 9 moles of H2O to grams.

This can be done as shown below:

Molar mass of H2O = (2x1) + 16 = 18g/mol

Mole of H2O = 9 moles

Mass of H2O =..?

Mole = mass / molar mass

9 = mass of H2O /18

Cross multiply

Mass of H2O = 9 x 18

Mass of H2O = 162g

Therefore, 162g of H2O were produced from 3 moles of C2H6.

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What is the mass of 1.84 mol NaCl? Give your
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The mass of an erlenmeyer flask is 85.135 g. after 10.00 ml of water is added to the flask, the mass of the flask and the water
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Subtracting the mass of (flask+water) from the empty flask gives:
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What is the age of mummified primate skin that contains 8.25% of the original quantity of 14C?
rjkz [21]

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20619.4793 years

Explanation:

The half life of carbon-14 = 5730 years

The formula for the half life for a first order kinetic reaction is:

t_{1/2}=\frac {ln\ 2}{k}

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t_{1/2} is the half life

k is the rate constant.

Thus rate constant is:

5730 years=ln(2)/k

k = 1.21×10⁻⁴ years ⁻¹

Using integrated rate law as:

ln\ \frac {A_t}{A_0}=-k\times t

Where,

A_t is the concentration at time t

A_0 is the initial concentration

Given that the final concentration contains 8.25 % of the original quantity which means that:

\frac {A_t}{A_0}=0.0825

So,

ln(.0825)= -1.21×10⁻⁴×t

<u> t = 20619.4793 years</u>

<u></u>

8 0
3 years ago
What is the [OH-] if the [H3O+] is 1 x 10 -6?
Mariulka [41]

The answer is [OH⁻] = 1 x 10⁻⁸.

To find OH⁻, divide the ionic product of water by [H₃O⁺] as :

<u>OH⁻ + H₃O⁺ = H₂O</u>

<u />

  • [OH⁻] = 1 x 10⁻¹⁴ / 1 x 10⁻⁶
  • [OH⁻] = 1 x 10⁻⁸
5 0
2 years ago
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