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Igoryamba
2 years ago
7

Calculate the mass of copper that could be made from 4.0g of copper oxide

Chemistry
1 answer:
Licemer1 [7]2 years ago
7 0

The mass of copper that will be produced from copper oxide is determined as 3.19 g.

<h3>Mass of copper produced from copper oxide</h3>

The mass of copper that will be produced from copper oxide is calculated as follows;

2Cu + O₂  -----> 2CuO

2          1             2

2(63.5) ------------ 2(79.5)

x ---------------------- 4 g

x = (4 x 2 x 63.5)/(2 x 79.5)

x = 3.19 g

Thus, the mass of copper that will be produced from copper oxide is determined as 3.19 g.

Learn more about copper here: brainly.com/question/24856041

#SPJ1

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Balance equation for. _Mg + _H3(PO4) --_Mg3(PO4)2+ _H2
Katena32 [7]
3Mg + 2H3(PO4) —> Mg3(PO4)2 + 3H2

I think
3 0
3 years ago
hich statement is true? A. An acid with a large pKa will be a better conductor of electricity than one with a smaller pKa. B. An
xz_007 [3.2K]

Answer:

\boxed{\text{B is correct}}

Explanation:

Kₐ and pKₐ are measures of the strength of an acid. For example,

HX + H₂O ⇌ H₃O⁺ + X⁻;  Kₐ = 10¹⁰,  pKₐ = -10

HA + H₂O ⇌ H₃O⁺ + A⁻; Kₐ = 10⁻¹⁰, pKₐ =  10

HX is a strong acid, because it has a larger Kₐ, that is, the position of equilibrium lies far to the right.

However, pKₐ is the negative logarithm of Kₐ, so HX has the smaller pKₐ.

Similarly, Ha is a weak acid, but it has the larger pKₐ.

Strong acid: Large Kₐ ⇔ Low pKₐ

Weak acid:   Small Kₐ ⇔ High pKₐ

A is wrong. HA is a weak acid, so it produces only a few hydronium ions.

B is correct. The rate of corrosion depends on the concentration of hydronium ions. HA is a weak acid, so it is less corrosive than an acid with a small pKₐ.

C is wrong. HX is a strong acid, so there are more ions to carry the current. HX will be a good conductor of electricity.

D is wrong. HX is a strong acid, so it provides more hydronium ions and is more corrosive.

E is wrong. HX is a strong acid, so it provides more hydronium ions to stimulate the taste buds.

\boxed{\textbf{B is correct}}

7 0
4 years ago
In a coffee-cup calorimeter, 1 mol NaOH and 1 mol HBr initially at 22.5 oC (Celsius) are mixed in 100g of water to yield the fol
zavuch27 [327]

Answer:

ΔH = -55.92 kJ

Explanation:

<u>Step 1:</u> Data given

1 mol NaOH and 1 mol HBr initially at 22.5 °C are mixed in 100g of water

After mixing the temperature rises to 83 °C

Specific heat of the solution = 4.184 J/g °C

Molar mass of NaOH = 40 G/mol

Molar mass of HBr = 80.9 g/mol

<u>Step 2: </u>The balanced equation

NaOH + HBr → Na+(aq) + Br-(aq) + H2O(l)

<u>Step 3:</u> mass of NaOH

Mass = moles * Molar mass

Mass NaOH = 1 * 40 g/mol

Mass NaOH = 40 grams

Step 4: Mass of HBr

Mass HBr = 1 mol * 80.9 g/mol

Mass HBr = 80.9 grams

Step 5: Calculate ΔH

ΔH = m*c*ΔT

ΔH= (100 + 40 + 80.9) * 4.184 * (83-22.5)

ΔH= 220.9 * 4.184 * 60.5

ΔH= 55916.86 J = 55.92 kJ

Since this is an exothermic reaction, the change in enthalpy is negative.

ΔH = -55.92 kJ

4 0
4 years ago
Used to pick up or hold hot objects
Deffense [45]

In Chemistry class, tongs are used to pick up or hold hot objects.

4 0
3 years ago
Read 2 more answers
How much HCl is produced from the reaction of an excess of HSbCl4 with 3 moles H2S in the following reaction? HSbCl4 + H2S → Sb2
Fudgin [204]

Answer:

We will produce 8.0 moles of HCl , this is 291.7 grams HCl

Explanation:

Step 1: Data given

Number moles of H2S = 3.0 moles

Step 2: The balanced equation

2HSbCl4 + 3H2S → Sb2S3 + 8HCl

Step 3: Calculate moles HCl

For 2 moles HSbCl4 we need 3 moles H2S to produce 1mol Sb2S3 and 8 moles HCl

For 3.0 moles H2S we'll have 8.0 moles HCl

Step 4: Calculate mass HCl

Mass HCl = moles HCl * molar mass HCl

Mass HCl = 8.0 moles * 36.46 g/mol

Mass HCl = 291.7 grams

We will produce 8.0 moles of HCl , this is 291.7 grams HCl

8 0
4 years ago
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