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andre [41]
2 years ago
5

Can anybody pls help me with chemistry how to balance an equation of class 7 ??? pls

Chemistry
2 answers:
Natalka [10]2 years ago
6 0

Answer:

This\:may\: help

Arisa [49]2 years ago
4 0

Answer:

(1) Write down the chemical reaction in the form of word equation,keeping reactants on left hand side and products on right hand side.

(2) Write symbol and formula of all reactants and products in word equation. (3) Balance the equation by multiplying the symbols and formula by smallest possible figures.

You might be interested in
One mole of water weights?
Gemiola [76]

Answer:

c 18.0ml

Explanation:

The average mass of one H2O molecule is 18.02 amu. The number of atoms is an exact number, the number of mole is an exact number; they do not affect the number of significant figures. The average mass of one mole of H2O is 18.02 grams. This is stated: the molar mass of water is 18.02 g/mol.

8 0
2 years ago
Which of the following is an inorganic compound?<br> AgNO3<br> C6H12<br> СНОН<br> C₂H7N
Lemur [1.5K]

Answer:

AgNO3

Explanation:

Silver nitrate (AgNO3) is an inorganic compound. Organic compounds usually have 1+ C.

4 0
3 years ago
PLEASE HELP ME ASAPPPPP What is the density of a piece of cardboard that has a mass of 250 g and volume of 46 mL? *
Roman55 [17]

Answer:

The answer is

<h2>5.43 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}  \\

From the question

mass = 250 g

volume = 46 mL

The density is

density =  \frac{250}{46}  \\  = 5.4347826...

We have the final answer as

<h3>5.43 g/mL</h3>

Hope this helps you

6 0
3 years ago
You have 1.6 x10 21 atoms of oxygen, what is the mass of that number of atoms
iren [92.7K]

Answer: 166.023×1023

Explanation:

Mass of 6.023×1023 atoms of oxygen = gram atomic mass of oxygen.

Mass of 6.023×1023 atoms of oxygen = 16g

∴ Mass of 1 atom of oxygen =166.023×1023

6 0
3 years ago
How many moles of k3po4 can be formed when 4.4 moles of h3po4 react with 3.8 moles of koh? h3po4 + koh yields h2o + k3po4 be sur
schepotkina [342]

the balanced chemical equation for the reaction is as follows

H₃PO₄ + 3KOH ---> K₃PO₄ + 3H₂O

stoichiometry of H₃PO₄ to KOH is 1:3

first we have to find which the limiiting reactant is

as the amount of product formed depends on the amount of limiting reactant present

number of H₃PO₄ moles reacted - 4.4 mol

if H₃PO₄ is the limiting reactant

1 mol of H₃PO₄ reacts with 3 mol of KOH

then 4.4 mol of H₃PO₄ reacts with - 3 x 4.4 mol = 13.2 mol of KOH

but only 3.8 mol of KOH is present

therefore KOH is the limiting reactant


stoichiometry of KOH to K₃PO₄ is 3:1

number of KOH moles reacted - 3.8 mol

therefore number of K₃PO₄ formed = number of KOH moles reacted / 3

= 3.8 mol / 3 = 1.3 mol


answer is 1.3 mol of K₃PO₄


3 0
3 years ago
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