Answer:
See the attached file for the design.
Explanation:
Find attached for the explanation.
Answer:
<em>minimum required diameter of the steel linkage is 3.57 mm</em>
<em></em>
Explanation:
original length of linkage l = 10 m
force to be transmitted f = 2 kN = 2000 N
extension e = 5 mm= 0.005 m
maximum stress σ = 200 N/mm^2 = 
maximum stress allowed on material σ = force/area
imputing values,
200 = 2000/area
area = 2000/(
) =
m^2
recall that area = 
=
= 
= 
=
m = 3.57 mm
<em>maximum diameter of the steel linkage d = 3.57 mm</em>
Answer:
i)ω=3600 rad/s
ii)V=7059.44 m/s
iii)F=1245.8 N
Explanation:
i)
We know that angular speed given as

We know that for one revolution
θ=2π
Given that time t= 2 hr
So
ω=θ/t
ω=2π/2 = π rad/hr
ω=3600 rad/s
ii)
Average speed V

Where M is the mass of earth.
R is the distance
G is the constant.
Now by putting the values


V=7059.44 m/s
iii)
We know that centripetal fore given as

Here given that m= 200 kg
R= 8000 km
so now by putting the values


F=1245.8 N
<u>Answer:</u>
The plasma membrane encloses specific structures.
<u>Explanation:
</u>
plasma membrane is also called as cell membrane. Plasma membrane only allows the particle to get in and pass out of the cell by osmosis and diffusion method from the outside environment. It is responsible for the molecular traffic inside the cell.
It helps in maintaining the shape of the cell. It has many proteins in it. Therefore cell membrane are responsible for having specific structures.
Answer:
The shortest distance d to the edge of the plate is 66.67 mm
Concepts and reason
Moment of a force:
Moment of a force refers to the propensity of the force to cause rotation on the body it acts upon. The magnitude of the moment can be determined from the product of force’s magnitude and the perpendicular distance to the force.
Moment(M) = Force(F)×distance(d)
Moment of inertia ( I )
It is the product of area and the square of the moment arm for a section about a reference. It is also called as second moment of inertia.
First prepare the free body diagram of sectioned plate and apply moment equilibrium condition and also obtain area and moment of inertia of rectangular cross section. Finally, calculate the shortest distance using the formula of compressive stress (σ) in combination of axial and bending stress
Solution and Explanation:
[Find the given attachments]