The Gravitationa potential energy of the mass (PEG) is given by:

where
m is the mass
g is the gravitational acceleration
h is the heigth of the mass above the reference level (the ground)
In this problem,

and

, therefore the gravitational potential energy of the mass is:
This item is solved through the concept of the conservation of momentum which states that the momentum before and after collision should be equal.
momentum = mass x velocity
(1,600 kg)(16 m/s) + (1.0x10^3 kg)(10 m/s) = (1600 + 1000 kg)(x)
The value of x is 13.69 m/s. Thus, their final speed is approximately letter D. 14 m/s.
The best explanation for the difference in time is: A. The difference in weight doesn't affect the time, but they are affected differently by air resistance.
<h3>What is weight?</h3>
Weight can be defined as the force acting on an object or a physical body due to the effect of gravity. Also, the weight of an object (body) is typically measured in Newton.
<h3>The factors that affect weight.</h3>
Some of the factors that affect the weight that is possessed by an object or a physical body include the following:
In conclusion, the weight possessed by the shoe and shirt has no effect on time but would be affected differently by air resistance.
Read more on weight here: brainly.com/question/13833323
The initial speed of car A is 15.18 m/s.
Momentum is defined as mass in motion. If there are two objects (the two objects in motion or only one object in motion and the other in stationary) that collide and no other forces work in the system, the law of momentum conservation applies in the system.
p=p'
pa+pb = pa'+pb'
(ma×va) + (mb×vb) = (ma×va') + (mb×vb')
- ma = mass of object A (kg) = 1,783 kg
- mb = mass of object B (kg) = 1,600 kg
- va = speed of object A before collides (m/s)
- va' = speed of object A after collides (m/s) = 8 m/s
- vb = speed of object B before collides (m/s) = 0 m/s
- vb' = speed of object B after collides (m/s) = 8 m/s
- p = momentum before collision (Ns)
- p' = momentum after collision (Ns)
(ma×va) + (mb×vb) = (ma×va') + (mb×vb')
(1,783×va) + (1,600×0) = (1,783×8) + (1,600×8)
(1,783×va) + 0 = 14,264+12,800
(1,783×va) = 27,064

va = 15.18 m/s
Learn more about The law of momentum conservation here: brainly.com/question/7538238
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