Simplify -62 ÷ 12 - 2(-7). -17 35 -35 11

Move numbers to the blanks to show a meaning of 5×2 = 10

MrRissso [65]

Answer:

The expression 5 × 2 = 10 means:

10 is 5 times as many as 2.

Step-by-step explanation:

Given the expression

5 × 2 = 10

From the expression, it is clear that we can determine that when we multiply 2 by 5 to get 10.

In other words, we can determine the value 10 by:

2+2+2+2+2 = 10

It means 10 is 5 times as many as 2.

Therefore, the expression 5 × 2 = 10 means:

10 is 5 times as many as 2.

6 0

3 years ago

Find the quotient. HELP ASAP PLEASE!!

telo118 [61]

-4/9/-1/3=4/3
HOPE THIS HELPED! IM NOT THAT GREAT AT MATH! SORRY IF IM WRONG!

3 0

2 years ago

What am I supposed to say on here the question is in the picture

Viktor [21]

The answer is Function A. This is because Function A has a higher y-intercept than Function B. #brainliest

8 0

2 years ago

Read 2 more answers

If a square has side lenght 3m, than its perimeter is 12m.

Luda [366]

Fu you ahole hhhhhhhhhhhhhhhhhhhhhhhhhh

7 0

3 years ago

Find the integral using substitution or a formula.

Nadusha1986 [10]

$\rm \int \dfrac{x^2+7}{x^2+2x+5}~dx$

Derivative of the denominator:
$\rm (x^2+2x+5)'=2x+2$

Hmm our numerator is 2x+7. Ok this let's us know that a simple u-substitution is NOT going to work. But let's apply some clever Algebra to the numerator splitting it up into two separate fractions. Split the +7 into +2 and +5.

$\rm \int \dfrac{x^2+2+5}{x^2+2x+5}~dx$

and then split the fraction,

$\rm \int \dfrac{x^2+2}{x^2+2x+5}~dx+\int\dfrac{5}{x^2+2x+5}~dx$

Based on our previous test, we know that a simple substitution will work for the first integral: $\rm \quad u=x^2+2x+5\qquad\to\qquad du=2x+2~dx$

So the first integral changes,

$\rm \int \dfrac{1}{u}~du+\int\dfrac{5}{x^2+2x+5}~dx$

integrating to a log,

$\rm ln|x^2+2x+5|+\int\dfrac{5}{x^2+2x+5}~dx$

Other one is a little tricky. We'll need to complete the square on the denominator. After that it will look very similar to our arctangent integral so perhaps we can just match it up to the identity.

$\rm x^2+2x+5=(x^2+2x+1)+4=(x+1)^2+2^2$

So we have this going on,

$\rm ln|x^2+2x+5|+\int\dfrac{5}{(x+1)^2+2^2}~dx$

Let's factor the 5 out of the intergral,
and the 4 from the denominator,

$\rm ln|x^2+2x+5|+\frac54\int\dfrac{1}{\frac{(x+1)^2}{2^2}+1}~dx$

Bringing all that stuff together as a single square,

$\rm ln|x^2+2x+5|+\frac54\int\dfrac{1}{\left(\dfrac{x+1}{2}\right)^2+1}~dx$

Making the substitution: $\rm \quad u=\dfrac{x+1}{2}\qquad\to\qquad 2du=dx$

giving us,

$\rm ln|x^2+2x+5|+\frac54\int\dfrac{1}{\left(u\right)^2+1}~2du$

simplying a lil bit,

$\rm ln|x^2+2x+5|+\frac52\int\dfrac{1}{u^2+1}~du$

and hopefully from this point you recognize your arctangent integral,

$\rm ln|x^2+2x+5|+\frac52arctan(u)$

undo your substitution as a final step,
and include a constant of integration,

$\rm ln|x^2+2x+5|+\frac52arctan\left(\frac{x+1}{2}\right)+c$

Hope that helps!
Lemme know if any steps were too confusing.

8 0

3 years ago