Answer:
The answer is 5 seconds;
Explanation:
<h3>a) We know that the speed(V) is 15 m/s and acc. (a) is 3 m/s^2 </h3><h3>b) The formula for the acceleration is a=
;</h3><h3>
Using this formula we can define the next equation:</h3><h3>
3 = , where t is the sought time. After solving the equation we get that t is 5; </h3><h3>
</h3><h3>
</h3><h3>
</h3>
The main difference between baseline activities and health-enhancing activities is that baseline activities maintain the status quo, while health-enhancing activities make things better.
i need to know the chemical eqaitions so......
Answer:
Explanation:
Atmospheric pressure = 7 x 10⁴ Pa
force on a disk-shaped region 2.00 m in radius at the surface of the ocean due to atmosphere = pressure x area
= 7 x 10⁴ x 3.14 x 2 x 2
= 87.92 x 10⁴ N
b )
weight, on this exoplanet, of a 10.0 m deep cylindrical column of methane with radius 2.00 m
Pressure x area
height x density x acceleration of gravity x π r²
= 10 x 415 x 6.2 x 3.14 x 2 x 2
=323168.8 N
c ) Pressure at a depth of 10 m
atmospheric pressure + pressure due to liquid column
= 7 x 10⁴ + 10 x 415 x 6.2 ( hρg)
= 7 x 10⁴ + 10 x 415 x 6.2
(7 + 2.57 )x 10⁴ Pa
9.57 x 10⁴ Pa
Radius of the rings = 10 / 2 = 5 cm 0.05m
Distance between them D = 15 cm = 0.15 m
The charge of left ring is Ql = -20 x 10^-9 C
The charge of right ring is Qr = 20 x 10^-9 C
Since it the electric field at the midpoint, it is same for both rings and the there are opposite charges the electric filed will be sum of electric field of both charges.
Electric field on the left El = (k x Ql) / (D/2)^2 = (4 x k x Ql) / D^2
Electric field on the Right Er = (k x Qr) / (D/2)^2 = (4 x k x Qr) / D^2
Electric field E = El + Er = ((4 x k x Ql) / D^2) + ((4 x k x Qr) / D^2)
E = 4k/ D^2 (Ql + Qr); k is Coulombs constant = 8.99 x 10^9 Nm2Câ’2
E = 4 x 8.99 x 10^9/ 0.15^2 (2n + 2n) = 1598 x 10^9 x 4 x 10^-9 = 6393 N/c
Force f = E x q, q being the charge at the mid point
Force = q x 6393 N/c = 6.393q x 10^3 N