PLEASE ANSWER ASAP BEFORE MY TEACHER AND MY MOM KILLES ME PLEASE ASAP
2 answers:
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Answer:
t = √2y/g
Explanation:
This is a projectile launch exercise
a) The vertical velocity in the initial instants ( = 0) zero, so let's use the equation
y = t -1/2 g t²
y= - ½ g t²
t = √2y/g
b) Let's use this time and the horizontal displacement equation, because the constant horizontal velocity
x = vox t
x = v₀ₓ √2y/g
c) Speeds before touching the ground
vₓ = vox = constant
=
- gt
= 0 - g √2y/g
= - √2gy
tan θ = Vy / vx
θ = tan⁻¹ (vy / vx)
θ = tan⁻¹ (√2gy / vox)
d) The projectile is higher than the cliff because it is a horizontal launch
Answer:
The moment of inertia will be increased by a factor of 1575
Explanation:
Let the moment of inertia of a wheel be given as;
where;
I is the moment of inertia of the wheel
m is mass of the wheel
r is radius of the wheel
when the mass is increased by a factor of 7 and the radius is increased by a factor of 15
Thus, the moment of inertia will be increased by a factor of 1575