3 years ago

Simplify completely sqrt of 20Y^8

Mathematics

1 answer:

brilliants [131]3 years ago

3 0

Answer:

Final answer is $2y^4 \sqrt{5}$ .

Step-by-step explanation:

Given expression is $\sqrt{20y^8}$ .

Now we need to smplify the given expression $\sqrt{20y^8}$ .

So begin with factoring 20 into two parts so that one part is perfect square number.

$\sqrt{20y^8}$

$=\sqrt{4 \times 5y^8}$

$=\sqrt{4 y^8} \times \sqrt{5}$

$=2y^4 \times \sqrt{5}$

Hence final answer is $2y^4 \sqrt{5}$ .

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