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2 years ago

Simplify completely sqrt of 20Y^8

Mathematics

1 answer:

brilliants [131]2 years ago

3 0

Answer:

Final answer is $2y^4 \sqrt{5}$ .

Step-by-step explanation:

Given expression is $\sqrt{20y^8}$ .

Now we need to smplify the given expression $\sqrt{20y^8}$ .

So begin with factoring 20 into two parts so that one part is perfect square number.

$\sqrt{20y^8}$

$=\sqrt{4 \times 5y^8}$

$=\sqrt{4 y^8} \times \sqrt{5}$

$=2y^4 \times \sqrt{5}$

Hence final answer is $2y^4 \sqrt{5}$ .

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The percentage of data values that must be within one, two, and three standard deviations of the mean for data having a bell-sha

xxMikexx [17]

Answer:

a. The empirical rule.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed(bell-shaped) random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

So the correct answer is:

a. The empirical rule.

3 0

3 years ago

Thomas bought a desk with a retail sales price of $129 and paid $10.32 sales tax. What is the sales tax rate where Thomas bough

ss7ja [257]

8% because 129x0.08=10.32

7 0

3 years ago

Read 2 more answers

Can I get some help please?

IrinaK [193]

Answer: A

Step-by-step explanation:

A linear function is described as:

https://tex.z-dn.net/?f=f(x)%20%3D%20ax%20%2B%20b

When the value of x = 0, then you're left with

https://tex.z-dn.net/?f=f(x)%20%3D%20b

In this question, the speed of sound is the linear function while the temperature is the independent variable. When T = 0, you're left with

https://tex.z-dn.net/?f=S(0)%20%3D%20331.4

Which means the speed of sound in air when temperature is 0°C is 331.4m/s.

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2 years ago

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A large tank is filled to capacity with 300 gallons of pure water. brine containing 5 pounds of salt per gallon is pumped into t

Licemer1 [7]

If $A(t)$ is the amount of salt in the tank at time $t$ , then the rate at which this amount changes over time is given by the ODE

$A'(t)=\dfrac{3\text{ gal}}{1\text{ min}}\cdot\dfrac{5\text{ lb}}{1\text{ gal}}-\dfrac{3\text{ gal}}{1\text{ min}}\cdot\dfrac{A(t)\text{ lb}}{300+(3-3)t\text{ gal}}$

$A'(t)+\dfrac1{100}A(t)=15$

We're told that the tank initially starts with no salt in the water, so $A(0)=0$ .

Multiply both sides by an integrating factor, $e^{t/100}$ :

$e^{t/100}A'(t)+\dfrac1{100}e^{t/100}A(t)=15e^{t/100}$
$\left(e^{t/100}A(t)\right)'=15e^{t/100}$
$e^{t/100}A(t)=1500e^{t/100}+C$
$A(t)=1500+Ce^{-t/100}$

Since $A(0)=0$ , we have

$0=1500+C\implies C=-1500$

so that the amount of salt in the tank over time is given by

$A(t)=1500(1-e^{-t/100})$

After 10 minutes, the amount of salt in the tank is

$A(10)=1500(1-e^{-1/10})\approx142.74\text{ lb}$

8 0

3 years ago

What is 5.823 rounded to the nearest whole<br> what is 3.147 rounded to the nearest whole

stich3 [128]

Answer:

6 and 3

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5.8 to the nearest whole is 6

3.147 to the nearest whole is 3

7 0

2 years ago