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frez [133]
3 years ago
6

Simplify completely sqrt of 20Y^8

Mathematics
1 answer:
brilliants [131]3 years ago
3 0

Answer:

Final answer is 2y^4 \sqrt{5}.

Step-by-step explanation:

Given expression is \sqrt{20y^8}.

Now we need to smplify the given expression \sqrt{20y^8}.

So begin with factoring 20 into two parts so that one part is perfect square number.

\sqrt{20y^8}

=\sqrt{4 \times 5y^8}

=\sqrt{4 y^8} \times \sqrt{5}

=2y^4 \times \sqrt{5}

Hence final answer is 2y^4 \sqrt{5}.

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Given the formula a= 12.b, solve for a when b= 4.5
kaheart [24]

Answer:

a=54

Step-by-step explanation:

Because the problem gives you the value of b simply plug it in the equation a=12b. The new equation should look like this when plugged in: a=12(4.5). Now multiply 12*4.5=54. The new equation would then become a=54

6 0
3 years ago
The LCM and GCF of 40 and m is 120 and 10 respectively. Find m​
il63 [147K]

Answer: 30

Step-by-step explanation:

Simple formula is

LCM*GCF=PRODUCT OF 2 NUMBERS

120 * 10 = 40 * x

1200 = 40x

x = 1200/40

x = 30

5 0
4 years ago
What is the integer that represents the temperature
Lerok [7]
The integer <span>that represents the temperature is 7.</span>
6 0
3 years ago
Enter the number that belongs in the green box.
vivado [14]
6x-7=4x+7
6x=4x+14
2x=14
x=7
6 0
3 years ago
Read 2 more answers
TRIGONOMETRY - Given the complex numbers <img src="https://tex.z-dn.net/?f=z_%7B1%7D%20%3D20%20cis%20226" id="TexFormula1" title
Norma-Jean [14]

This is easily done after writing both complex numbers in exponential form:

z_1=20\,\mathrm{cis}226^\circ=20e^{226^\circ i}

z_2=5\,\mathrm{cis}76^\circ=5e^{76^\circ i}

Then

\dfrac{z_1}{z_2}=\dfrac{20e^{226^\circ i}}{5e^{76^\circ i}}=4e^{(226-76)^\circ i}=4e^{150^\circ i}

In trigonometric form, this is

\dfrac{z_1}{z_2}=4\,\mathrm{cis}150^\circ=4(\cos150^\circ+i\sin150^\circ)=\boxed{-\dfrac{\sqrt3}2+\dfrac i2}

8 0
3 years ago
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