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3 years ago

Can a qaudrilateral be a square

Mathematics

2 answers:

inysia [295]3 years ago

6 0

Yes because the qaudrilaterals have to have 4 sides but it doesn't matter on the side lengths

malfutka [58]3 years ago

3 0

Yes quadrilaterals can be squares

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Janice bought 5 bags of gummy bears at $0.85 each and 9 packs of gum at $1.20 each for her class party.

STatiana [176]

5 times 0.85 = 4.25 gummy bears
9 times 1.20 = 10.80 gum
10.80 + 4.25 = 15.05 total<span />

6 0

3 years ago

Read 2 more answers

Christine baked a pumpkin pie. She ate 1/6. Her brother ate 1/3 of it and gave the left overs to his friends. What fraction of t

stiv31 [10]

Answer:3/6 of the pie to friends

Step-by-step explanation:

4 0

3 years ago

Try the numbers 22, 23, 24, 25 in the equation 4/3 = 32/d to test whether any of them is a solution. a. 23 is a solution. c. 24

S_A_V [24]

Answer:

c. 24 is a solution

Step-by-step explanation:

Given equation:

$\frac{4}{3}=\frac{32}{d}$

To test the numbers 22, 23, 24, 25 for the solution.

Solution:

In order to test the given number for the solution, we will plugin each number in the unknown variable $d$ and see if it satisfies the equation.

1) $d=22$

$\frac{4}{3}=\frac{32}{22}$

Reducing fraction to simplest form by dividing the numerator and denominator by their G.C.F.

$\frac{4}{3}=\frac{32\div 2}{22\div 2}$

$\frac{4}{3}=\frac{16}{11}$

The above statement can never be true and hence 22 is not a solution.

2) $d=23$

$\frac{4}{3}=\frac{32}{23}$

The fractions can no further be reduced.

The statement can never be true and hence 23 is not a solution.

3) $d=24$

$\frac{4}{3}=\frac{32}{24}$

Reducing fraction to simplest form by dividing the numerator and denominator by their G.C.F.

$\frac{4}{3}=\frac{32\div 8}{24\div 8}$

$\frac{4}{3}=\frac{4}{3}$

The above statement is always true and hence 24 is a solution.

4) $d=25$

$\frac{4}{3}=\frac{32}{25}$

The fractions can no further be reduced.

The statement can never be true and hence 25 is not a solution.

4 0

3 years ago

1. What is an equation of a line, in point-slope form, that passes through (1,-7) and has a slope of -2/3?

Nookie1986 [14]

1. What is an equation of a line, in point-slope form, that passes through (1,-7) and has a slope of -2/3?

Point Slope form y − y1 = m(x − x1)

Y1: -7 x1:1 slope :-2/3

Y-(-7)=-2/3(x-1)

Y+7=-2/3(x-1)

2. What is the equation of a line, in point-slope form, that passes through (-2,-6) and had a slope of 1/3?

Y-(-6)=1/3(x-(-2))

Y+6=1/3(x+2)

3.What is an equation in point-slope form of the line that passes through the points (4,5) and (-3,-1)

SlopeM: =change in y/change in x

M= -1-5/-3-4

M= -6/-7

M=6/7

So now slope:6/7, point (4,5)

Y-y1=m(x-x1)

Equation in point slope

Y-5=6/7(x-4)

6 0

3 years ago

1.Arsenic-74 is used to locate brain tumors. It has a half-life of 17.5 days. 90 mg wereused in a procedure. Write an equation t

Sophie [7]

$1)\text{ }N_t\text{ = 90\lparen}\frac{1}{2})^{\frac{t}{17.5}}$

2) 5.625 mg will be left

Explanation:

1) Half-life = 17.5 days

initial amount of Arsenic-74 = 90 mg

To get the equation, we will use the equation of half-life:

$\begin{gathered} N_t\text{ = N}_0(\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}} \\ where\text{ N}_t\text{ = amount remaining} \\ N_0\text{ = initial amount} \\ t_{\frac{1}{2}\text{ }}\text{ = half-life} \end{gathered}$ $N_t\text{ = 90\lparen}\frac{1}{2})^{\frac{t}{17.5}}$

2) we need to find the remaining amount of Arsenic-74 after 70 days

t = 70

$\begin{gathered} N_t=\text{ 90\lparen}\frac{1}{2})^{\frac{70}{17.5}} \\ N_t\text{ = 5.625 mg} \end{gathered}$

So after 70 days, 5.625 mg will be left

4 0

1 year ago