Question

How many moles are in 2.16 x 1024 atoms of silver??

Answer 1

2,16·10²⁴ = 21,6·10²³
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6,02·10²³ atoms ------ 1 mole of Ag
21,6·10²³ atoms ------ X
X = 21,6·10²³/6,02·10²³
X = 3,588 moles of silver

:)

Answer 2

Answer:

3.5868 moles of silver are equal to $2.16\times 10^{24}$ atoms.

Explanation:

Number of atoms = $n\times N_A$

n = moles of the compound or element

$N_A$= Avogadro number

$N_A=6.022\times 10^{23} mol^{-1}$

Moles of silver be x

Number of silver atoms = $2.16\times 10^{24}$ atoms

$2.16\times 10^{24}=x\times 6.022\times 10^{23}$

$x=\frac{2.16\times 10^{24}}{6.022\times 10^{23}mol^{-1}}=3.5868 moles$

3.5868 moles of silver are equal to $2.16\times 10^{24}$ atoms.