1) 0.89% m/v = 0.89 grams of NaCl / 100 ml of solution
=> 8.9 grams of NaCl in 1000 ml of solution = 8.9 grams of NaCl in 1 liter of solution
2) Molarity = M = number of moles of solute / liters of solution
=> calculate the number of moles of 8.9 grams of NaCl
3) molar mass of NaCl = 23.0 g /mol + 35.5 g/mol = 58.5 g / mol
4) number of moles of NaCl = mass / molar mass = 8.9 g / 58.5 g / mol = 0.152 mol
5) M = 0.152 mol NaCl / 1 liter solution = 0.152 M
Answer: 0.152 M
Answer:
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Explanation:
Heat require to boil 15.6 g iron from 122 C0to 355 C0 whereas,
Where, m is mass of iron
s is specific heat of iron
d T is change in temperature in celcius
If
1 cal = 4.2 J
Then,
Thus 0.389 k cal of enrgy is required by a 15.6 g Fe to reach to 355 C^0
