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Alika [10]
3 years ago
6

How many times will a skydiver reach terminal velocity before landing on the ground?.......... A. 0 B. 1 C. 3 D. 2

Physics
1 answer:
ludmilkaskok [199]3 years ago
5 0

Answer:

D. 2

Explanation:

The skydiver will reach terminal velocity when gravity = air resistance. When this occurs, he/she will no longer accelerate and his/her speed will be constant.

Once the skydiver opens the parachute, his/her speed will decrease suddenly, and again the air resistance increases due to the parachute's large area. Eventually, gravity will equal air resistance again and terminal velocity will be reached for the second time.

Even though the speeds are different, the first terminal velocity is much higher than the second one, this question refers to how many times terminal velocity is reached, not how many times the skydiver accelerates.

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Answer:

The acceleration of the ball is  a_y =  - 0.3672 \ m/s^2

Explanation:

From the question we are told that

       The maximum height the ball reachs is H_{max} =  42.24 \ m

       The horizontal component of the initial velocity of the ball is v_{ix} = 5.57 \ m/s

       The vertical component of the initial velocity of the ball is v_{iy} = = 16.18 m/s

The vertically motion of the ball can be mathematically represented as

       v_{fy}^2  =  v_{iy} ^2 + 2 a_{y} H_{max}

Here the final velocity at the maximum height is zero so v_{fy} = 0 \ m/s

Making the acceleration a_y the subject we have

        a_y =  \frac{v_{iy} ^2}{2H_{max}}

substituting values

      a_y =  - \frac{5.57^2}{2* 42.24}

      a_y =  - 0.3672 \ m/s^2

The negative sign shows that the direction of the acceleration is in the negative y-axis

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