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a_sh-v [17]
3 years ago
7

The animation shows a ball which has been kicked upward at an angle. Run the animation to watch the motion of the ball. Click in

itialize to set up the animation and start to run it.
Ghosts are left by the ball once per second. The animation can also be paused and moved forward in single frame mode using the step button. The cursor can be used to read the (x,y) coordinates of a position in the grid by holding down the left mouse button. Assume the grid coordinates read out in meters. When entering components, presume that x is positive to the right and y is positive upwards. Note that this ball is NOT being kicked on Earth. Do not expect an acceleration of 9.80 m/s2 downward, though you can presume that gravity is acting straight down. Use this animation to answer the following questions. Note that there are a number of different ways to go about each of the following questions. Your answer needs to be within 5% of the correct answer for credit. Please enter your answer to 3 significant digits.

What is the maximum height which the ball reaches? 42.24 m

What is the horizontal component of the initial velocity of the ball? 5.57 m/s

What is the vertical component of the initial velocity of the ball? 16.18 m/s

What is the vertical component of the acceleration of the ball? _____????
Physics
1 answer:
sergejj [24]3 years ago
6 0

Answer:

The acceleration of the ball is  a_y =  - 0.3672 \ m/s^2

Explanation:

From the question we are told that

       The maximum height the ball reachs is H_{max} =  42.24 \ m

       The horizontal component of the initial velocity of the ball is v_{ix} = 5.57 \ m/s

       The vertical component of the initial velocity of the ball is v_{iy} = = 16.18 m/s

The vertically motion of the ball can be mathematically represented as

       v_{fy}^2  =  v_{iy} ^2 + 2 a_{y} H_{max}

Here the final velocity at the maximum height is zero so v_{fy} = 0 \ m/s

Making the acceleration a_y the subject we have

        a_y =  \frac{v_{iy} ^2}{2H_{max}}

substituting values

      a_y =  - \frac{5.57^2}{2* 42.24}

      a_y =  - 0.3672 \ m/s^2

The negative sign shows that the direction of the acceleration is in the negative y-axis

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The energy from 0.015 moles of octane was used to heat 250 grams of water. The temperature of the water rose from 293.0 K to 371
arsen [322]

Answer : The correct option is, (B) -5448 kJ/mol

Explanation :

First we have to calculate the heat required by water.

q=m\times c\times (T_2-T_1)

where,

q = heat required by water = ?

m = mass of water = 250 g

c = specific heat capacity of water = 4.18J/g.K

T_1 = initial temperature of water = 293.0 K

T_2 = final temperature of water = 371.2 K

Now put all the given values in the above formula, we get:

q=250g\times 4.18J/g.K\times (371.2-293.0)K

q=81719J

Now we have to calculate the enthalpy of combustion of octane.

\Delta H=\frac{q}{n}

where,

\Delta H = enthalpy of combustion of octane = ?

q = heat released = -81719 J

n = moles of octane = 0.015 moles

Now put all the given values in the above formula, we get:

\Delta H=\frac{-81719J}{0.015mole}

\Delta H=-5447933.333J/mol=-5447.9kJ/mol\approx -5448kJ/mol

Therefore, the enthalpy of combustion of octane is -5448 kJ/mol.

5 0
3 years ago
A small grinding wheel has a moment of inertia of 4.0*10-5kgm2. What net torque must be applied to the wheel for its angular acc
kvv77 [185]

Hi there!

We can use the rotational equivalent of Newton's Second Law:

\huge\boxed{\Sigma \tau = I \alpha}

Στ = Net Torque (Nm)

I = Moment of inertia (kgm²)

α = Angular acceleration (rad/sec²)

We can plug in the given values to solve.

\Sigma \tau = (4 * 10^{-5})(150) = \boxed{0.006 Nm}

4 0
3 years ago
I need the answer a sap please
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D is the answer
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7 0
3 years ago
Imagine that you're standing in a large room when a loud noise is made. You begin hearing a series of echoes. Which characterist
german
The characteristic of sound that would best explain the series of echoes you are hearing would be reverberation. It is created when a sound wave is being reflected to the surfaces causing it to have a many reflection building up and decaying as these waves are being absorbed bu the surfaces in the area which could be tables, chairs, people or the air. Reverberation is the group of the reflected sounds in an enclosed area. 
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3 years ago
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It has been proposed that extending a long conducting wire from a spacecraft (a "tether") could be used for a variety of applica
denis23 [38]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The angle between shuttle's velocity and the Earth's field is  \theta =   24.2^o

Explanation:

From the question we are told that

     The length of eire let out is  L = 250 \ m

      The emf generated is \epsilon = 40 V

      The earth magnetic field is B = 5.0 *10^{-5} T

     The speed of the shuttle and tether is v =  7.80 * 10^3 \  m/s

The emf generated is mathematically represented as

                             \epsilon = L\ v\ B\ sin \ \theta

making \theta  the subject of the formula

                        \theta =   sin ^{-1}[ \frac{\epsilon}{L  * B  *v} ]

substituting values

                        \theta =   sin ^{-1}[ \frac{40}{250  * (5*10^{-5})  *(7.80 *10^{3})} ]

                        \theta =   24.2^o

6 0
3 years ago
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