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Alecsey [184]
3 years ago
12

If the textbook weighs 19.6 newtons on venus,what is the strength of gravity on venus?

Physics
2 answers:
Natalija [7]3 years ago
8 0

Answer:

The strength of gravity on Venus is 8.9\ m/s^2.

Explanation:

Given that,

Let the mass of the textbook, m = 2.2. kg (let is assume)

Weight of the textbook, W = 19.6 N

We need to find the strength of gravity on Venus. We know that the weight of an object is given by the product of mass and acceleration due to gravity. It is given by :

W=mg

g is strength of gravity on the Venus

g=\dfrac{W}{m}

g=\dfrac{19.6\ N}{2.2\ kg}

g=8.9\ m/s^2

So, the strength of gravity on Venus is 8.9\ m/s^2. Hence, this is the required solution.

Greeley [361]3 years ago
4 0

The correct answer is 8.9 m/s2

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Light waves from the sun can travel through outer space and reach the earth. This suggests that light is a(n)
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Answer:

D

Explanation:

The sun emits electromagnetic radiation.

6 0
4 years ago
Roger pushes a box on a 30° incline. If he applies a force of 60 newtons parallel to the incline and displaces the box 10 meters
Dmitry [639]
Work = Force * distance

He's going up an incline but pushing parallel to the ground. Draw out a diagram to show what's going on. )


Work =  force* distance*Cos(incline angle)
60 N force * 10 meters * cos(30)
= 519.61 J

7 0
4 years ago
Ngan has a weight of 314.5 N on Mars and a weight 833.0 N on Earth. What is Ngan's mass on Earth?
mr_godi [17]

Ngan's mass on earth is 85kg.

Ngan has a weight on Mars = 14.5 N

Ngan’s weight on Earth = 833.0 N

Ngan’s mass on Earth = ?

<span>Fg,earth = mg(earth)</span>

<span>M = Fg,earth </span><span>/ g(earth)</span>

<span>M = 833.0 N / 9.8 m/s2</span>

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4 0
3 years ago
Read 2 more answers
Define gravitational force in your own words.
Nat2105 [25]

Gravitational force is the universal force of attraction acting between all matter.

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3 0
3 years ago
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A copper transmission cable 180 km long and 11.0 cm in diameter carries a current of 135 A.
zheka24 [161]

Answer:

a) 43.98 V

b) E = 21.37 MJ

Explanation:

Parameters given:

Length of cable = 180 km = 180000 m

Diameter of cable = 11 cm = 0.11 m

Radius = 0.11 / 2 = 0.055 m

Current, I = 135 A

a) To find the potential drop, we have to find the voltage across the wire:

V = IR

=> V = IρL / A

where R = resistance

L = length of cable

A = cross-sectional area

ρ = resistivity of the copper wire = 1.72 * 10^(-8) Ωm

Therefore:

V = (135 * 1.72 * 10^(-8) * 180000) / (π * 0.055^2)

V = 43.98 V

The potential drop across the cable is 43.98 V

b) Electrical energy is given as:

E = IVt

where t = time taken = 1 hour = 3600 s

Therefore, the energy dissipated per hour is:

E = 135 * 43.98 * 3600

E = 21.37 MJ (mega joules, 10^6)

7 0
3 years ago
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