Y = T+3 (i)
T = H+2 (ii)
Y = 2*H (iiii)
T = H+2 therefore H = T-2
Substitute H=T-2 into (iii)
Y=2*H
Y=2*(T-2)
Y=2T-4
Now substitute that Y into (i)
(i) says Y = T+3
2T-4=T+3
2T-T-4=3
T-4=3
T=3+4
T=7
Then from (i) Y=T+3 = 7+3 =10
Y=10
And from (iii) Y=2*H
If Y = 10, then H = 5
Answer: (f-g)(2)=14
Step-by-step explanation:
(f – g) (-2) means the same as subtracting f(2) and g(2). Since we are given f(x) and g(x), we can use them to solve. There are two ways to solve. One is to find f(2) and g(2), and then subtract them. Another way is to do (f-g)(x), then plug in x=2. I will show both methods.
Method 1
f(2)=3(2)²+1 [exponent]
f(2)=3(4)+1 [multiply]
f(2)=12+1 [add]
f(2)=13
g(2)=1-(2) [subtract]
g(2)=-1
(f-g)(2)=13-(-1) [subtract f(2) and g(2)]
(f-g)(2)=14
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Method 2
(f-g)(x)=3x²+1-(1-x) [distribute -1]
(f-g)(x)=3x²+1-1+x [combine like terms]
(f-g)(x)=3x²+x
(f-g)(2)=3(2)²+2 [plug in x=2, exponent]
(f-g)(2)=3(4)+2 [multiply]
(f-g)(2)=12+2 [add]
(f-g)(2)=14
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Now, we know that (f-g)(2)=14. We confirmed this with both methods.
6 • x + 6 • 9
I’m pretty sure this is right because you have to distribute the 6 to both of the numbers inside of the parentheses
Answer:
-10
Step-by-step explanation:
so,a=-10
A polynomial function is a function involving only non-negative (positive and 0) integer powers of 'x', i.e. all terms with ' 'x' have a non-negative integer power, such as a quadratic 
and so on.
Option E is the answer.
Rest all are wrong answers. they do not have positive integers.
