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Ivenika [448]
3 years ago
10

A cube of steel has dimension 0.2m x 02.m x 0.2m. What is the volume of the cube in cubic centimeters ?

Chemistry
1 answer:
drek231 [11]3 years ago
7 0

Answer:

8000

Explanation:

0.2 x 0.2 x 0.2

then m to cm^3

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Which answer below correctly identifies the type of change and the explanation when magnesium comes into contact with hydrochlor
Oliga [24]

Answer:

A chemical change because a temperature change occurred, the solid disappeared and a gas was produces

Explanation:

Magnesium reacts with hydrochloric acid releasing energy, and leading to the formation of  magnesium chloride and hydrogen gas. This is represented by the equation below:

Mg₍s₎ + 2HCl₍aq)⇒ MgCl₂₍aq₎ + H₂₍g₎

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How many grams of carbon are in 0.24 moles of carbon?
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Answer:

I'm converting this if I could remember how

2.882568

2 110321/ 125000

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3 years ago
Which is a property of an ideal gas?
AlekseyPX
HEY THERE!

THE ANSWER IS: the properties of an ideal gas are: An ideal gas consists of a large number of identical molecules. The volume occupied by the molecules themselves is negligible compared to the volume occupied by the gas. The molecules obey Newton's laws of motion, and they move in random motion.

CREDITS:
<span>physics.bu.edu/~duffy/py105/Idealgas.htm</span>
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A 15.0 g sample of nickel metal is heated to 100.0 degrees C and dropped into 55.0 g of water, initially at 23.0 degrees C. Assu
OLEGan [10]

Answer: The final temperature of nickel and water is  25.2^{o}C.

Explanation:

The given data is as follows.

   Mass of water, m = 55.0 g,

  Initial temp, (t_{i}) = 23^{o}C,      

  Final temp, (t_{f}) = ?,

  Specific heat of water = 4.184 J/g^{o}C,      

Now, we will calculate the heat energy as follows.

           q = mS \Delta t

              = 55.0 g \times 4.184 J/g^{o}C \times (t_{f} - 23^{o}C)

Also,

    mass of Ni, m = 15.0 g,

   Initial temperature, t_{i} = 100^{o}C,

   Final temperature, t_{f} = ?

 Specific heat of nickel = 0.444 J/g^{o}C

Hence, we will calculate the heat energy as follows.

          q = mS \Delta t

             = 15.0 g \times 0.444 J/g^{o}C \times (t_{f} - 100^{o}C)      

Therefore, heat energy lost by the alloy is equal to the heat energy gained by the water.

              q_{water}(gain) = -q_{alloy}(lost)

55.0 g \times 4.184 J/g^{o}C \times (t_{f} - 23^{o}C) = -(15.0 g \times 0.444 J/g^{o}C \times (t_{f} - 100^{o}C))

       t_{f} = \frac{25.9^{o}C}{1.029}

                 = 25.2^{o}C

Thus, we can conclude that the final temperature of nickel and water is  25.2^{o}C.

6 0
3 years ago
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