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Fynjy0 [20]
3 years ago
7

If 65.0 g of aspirin (C₉H₈O₄) are produced from 79.8 g of C₇H₆O₃, what is the percent yield from the reaction below?

Chemistry
1 answer:
lyudmila [28]3 years ago
7 0

Answer:

f 65.0 g of aspirin (C₉H₈O₄) are produced from 79.8 g of C₇H₆O₃, what is the percent yield from the reaction below?

C₇H₆O₃ (s) + C₄H₆O₃ (s) → C₉H₈O₄ (s) + HC₂H₃O₂ (aq).

Explanation:

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Answer:

<h3>The answer is 0.075 moles</h3>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L}  \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

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From the question we have

n =  \frac{4.5 \times  {10}^{22} }{6.02 \times  {10}^{23} }  \\  = 0.074750830...

We have the final answer as

<h3>0.075 moles</h3>

Hope this helps you

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