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3 years ago

If 65.0 g of aspirin (C₉H₈O₄) are produced from 79.8 g of C₇H₆O₃, what is the percent yield from the reaction below?

Chemistry

1 answer:

lyudmila [28]3 years ago

7 0

Answer:

f 65.0 g of aspirin (C₉H₈O₄) are produced from 79.8 g of C₇H₆O₃, what is the percent yield from the reaction below?

C₇H₆O₃ (s) + C₄H₆O₃ (s) → C₉H₈O₄ (s) + HC₂H₃O₂ (aq).

Explanation:

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1. The answer to the research question is the...

katovenus [111]

Answer:

1. A claim

2. B evidence

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4 years ago

Consider the reaction in the lead-acid cell pb(s) pbo2(s) 2 h2so4(aq) 2 pbso4(aq) 2 h2o(l) for which e°cell = 2. 04 v at 298 k.

aleksley [76]

δg° for the reaction having e° cell = 2.04v. is 393.658kJ.

The lead (Pb) in the lead storage battery act as an anode

<h3>What is Voltaic Cell?</h3>

A voltaic cell or galvanic cell is an electrochemical cell that uses chemical reactions to produce electrical energy.

<h3>Parts of voltaic cell</h3>

Anode where oxidation occurs Cathode where reduction occurs.

Therefore, Pb acts as anode and PbO2 act as a cathode.

Given,

E° cell = 2.04v

Faraday constant= 96485 C/mol

Moles of electron transferred n= 2

∆G = -nFE°

= -2 × 96485 × 2.04

= 393.658kJ

Thus we concluded that the δg° for the reaction having e° cell = 2.04v. is 393.658kJ.

learn more about voltaic cell :

brainly.com/question/1370699

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8 0

2 years ago

HURRY PLEASE

katrin2010 [14]

Answers:

Question 1:

The diagram for gallium will have flat, horizontal lines at 30 and 2204 °C.

Questoin 2:

The diagram for methane will have a diagonal line representing the liquid phase between -183°C and -162°C.

Question 3:

For gold, the boiling point corresponds to the y-value at 2856 °C of the top horizontal line

Question 4.

For nitrogen, the line at -210°C will be flat, which represents the change from a solid to a liquid

Explanations:

Question 1:

The diagram for gallium will have flat, horizontal lines at 30 and 2204 °C.

The table shows that the melting point of gallium is 30°C and its boiling point is 2204°C.

Melting point is the temperature at which the substace changes its state from solid to liquid. During that change, the temperature of the substance does not change, because the heat supplied is used to accomplish the phase change. So, the temperature is constant and that means that portion of the diagram is flat.

The same is valid during boiling: the temperature remains constant while the substance is passing from liquid to gas at the boiling point.

Questoin 2:

The diagram for methane will have a diagonal line representing the liquid phase between -183°C and -162°C.

Between the melting (-183°C) and boiling (-162°C) points of methane, its temperature will increase more or less linearly, which is represented with a diagonal (slant) line between those points. During this interval the heat is used to increase the temperature and no phase of change happens.

Question 3:

For gold, the boiling point corresponds to the y-value at 2856 °C of the top horizontal line

The table shows that the boiling point of gold is 2,856°C.

In a temperature-vs.-time diagram the temperature is represented on the vertical axis (y-value) and the time is represented on the horizontal axis.

Since, the temperature of the substance does not change during boiling, the line during the time that this change of phase is happening is flat. And since this temperatue is higher than the melting temperature, this is the top horizontal line in the diagram.

Question 4.

For nitrogen, the line at -210°C will be flat, which represents the change from a solid to a liquid

The table shows that the melting point of nitrogen is -210°C, that means that the temperature will remain constant at -210°C while the substance is absorbing heat to pass from solid to liquid.

In conclusion, you must remember that all the phase changes, melting (from solid to liquid), freezing (from liquid to solid), boilng (from liquid to gas), and condensing (from gas to liquid) happens at constant temperature, and so the temperature - vs. - time diagrams show flat lines (constant y-values) during those intervals of time.

4 0

3 years ago

Read 2 more answers

A hypothetical element has two main isotopes. One has a mass of 54 amu and the other has a mass of 56 amu. If the atomic weight

castortr0y [4]

Answer:

The answer to your question is: letter D

Explanation:

Data

Isotope mass 1 = 54 amu

Isotope mass 2 = 56 amu

Atomic weight = 54.37 amu

Percent abundance of isotope 2 = ? = X

Percent abundance of isotope 1 = 1 - x

Formula

Atomic weight = (Mass isotope 1)(1 - x) + (mass isotope 2)(x)

Process

Place the data in the formula and solve for x.

54.37 = 54( 1 - x) + 56x

54.37 = 54 - 54x + 56x

54.37 - 54 = -54x + 56x

0.37 = 2x

x = 0.37 / 2

x = 0.185

To find the percent multiply by 100

x = 0.185 x 100

x = 18.5 % = Mass of isotope 2

Mass of isotope 1 = 100 - 18.5 = 81.5 %

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4 years ago

Which pair of molecules is not a polar bond? A) N-O B) C-O C) O-H D)O-o

kolbaska11 [484]

D) O-O

The higher the difference in electronegativities of the two atoms, the more polar it is. Although oxygen is a very electronegative atom, it is bonded to itself which would make it a nonpolar bond.

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4 years ago

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