It is either a proton or a neutron . B
<h3>
How to identify the particle</h3>
The particle labeled with an X is a neutral atom or a proton which is symbolically represented as :
AZX
where,
Z = atomic number of the element and is known as the number of protons and number of electron (in the particle)
A = Mass number of the element which is represented as the sum of the protons and neutrons (in the nucleus)
Thus, the statement that best identifies the particle X is that it is either a proton or a neutron
Learn more about mass number here:
brainly.com/question/1805828
#SPJ1
One CC, or cubic centimeter, is equal to one mL, or milliliter.<span> </span>
If my memory serves me well, each period in the periodic table corresponds to a principal energy level. I think it's correct because periods are the horizontal rows and when you go down you always add <span> one to the principal energy level. Hope it is clear. Good luck!</span>
Here we have to draw the four isomers of the compound 3-bromo-4-fluorohexane.
The four isomers of the compound is shown in the figure.
In an organic molecule the chiral -C center is that where four (4) different groups are present. In 3-bromo-4-fluorohexane the 3 and 4 positions are chiral centers. The possible isomers of a molecule can be obtained from the formula 2n. As here 2 chiral centers are present thus number of stereoisomers will be 2×2 = 4.
The four different isomers as shown in the figure are 3R-, 4R-; 3S-, 4S; 3R, 4S and 3S-, 4R- 3-bromo-4-fluorohexane.
In the 3-bromo-4-fluorohexane the functional groups are -Br, C₂H₅, -C₃H₆F and -H for 3-position and -F, -C₂H₅, -C₃H₆ and -H for 4-position respectively.
The priority of the -3 position will be Br > C₃H₆F > C₂H₅ > H and for -4 position F > C₃H₆Br > C₂H₅ > H. If the rotation from the higher priority group to lower is clockwise and anticlockwise then the S- and R- notation are used respectively. However if the -H atom is present at the horizontal position then the notation will be reverse.
Thus the four isomers of the compound is shown.