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wlad13 [49]
3 years ago
9

Julie takes a cold glass of clear, colorless liquid out of the refrigerator and puts it on the table. As the liquid warms up to

room temperature, Julie sees bubbles of gas form in the liquid and rise to the surface. Which conclusion is best supported by Julie’s observations?
Chemistry
2 answers:
marysya [2.9K]3 years ago
8 0
The bubbles indicate that there is a gas dissolved in the liquid, which may remain dissolved when the liquid is very cold, inside the refrigerator.


When the temperature of the liquid increases, it reduces its ability to dissolve the gas and the gas escapes (bubbles) from the liquid.


At the end, the behavior of the liquid permits  you to conclude that the  liquid is a mixture because it has a gas dissolved in it.
Bess [88]3 years ago
5 0

D. The liquid is a mixture because it has a gas dissolved in a liquid.

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In a particular reaction, 53.8 g of liquid silicon tetrachloride is added to 65.0 g of solid magnesium to produce solid magnesiu
kotykmax [81]

Answer: Mg is the excess reactant for the forward reaction.

Explanation: It is a stoichiometry problem and solved with the help of given grams and using balanced equation. Grams of both the reactants are converted to moles and divided by their coefficients. The excess reactant is the one for which we get the highest number on doing above steps.

The balanced equation is:

SiCl_4(l)+2Mg(s)\rightarrow 2MgCl_2(s)+Si(s)

Molar mass of silicon tetra chloride is 169.9 gram per mol and the molar mass of Mg is 24.3 gram per mol.

53.8gSiCl_4(\frac{1mol}{169.9g})

= 0.317molSiCl_4

65.0gMg(\frac{1mol}{24.3g})

= 2.67 mol Mg

From balanced equation, the coefficient of silicon tetra chloride is 1 and that of Mg is 2. So, we will divide the moles of silicon tetra chloride by 1 and that of Mg by 2 and see which one gives highest number.

For silicon tetra chloride, \frac{0.317}{1}  = 0.317

and for Mg, \frac{2.67}{2}  = 1.34

The highest number is for Mg and so the excess reactant for the forward reaction is Mg.

7 0
3 years ago
Massive amounts of energy are contained in an atom's: Select one:
melamori03 [73]
Nucleus.
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6 0
3 years ago
How many ATOMS of OXYGEN are there in the following compound
STatiana [176]
6 Atoms!
Mg = 1 atom.
O = 4 atoms.
A = 1 atom.
5 0
3 years ago
Which scenario suggests that the results of an experiment are reliable?
BigorU [14]
The answer is B.

Hope this helps.
4 0
3 years ago
Read 2 more answers
How many liters of hydrogen gas will be produced at STP from the reaction of 7.179×10^23 atoms of magnesium with 54.219g of phos
Alexeev081 [22]

Answer: The volume of hydrogen gas produced will be, 12.4 L

Explanation : Given,

Mass of H_3PO_4 = 54.219 g

Number of atoms of Mg = 7.179\times 10^{23}

Molar mass of H_3PO_4 = 98 g/mol

First we have to calculate the moles of H_3PO_4 and Mg.

\text{Moles of }H_3PO_4=\frac{\text{Given mass }H_3PO_4}{\text{Molar mass }H_3PO_4}

\text{Moles of }H_3PO_4=\frac{54.219g}{98g/mol}=0.553mol

and,

\text{Moles of }Mg=\frac{7.179\times 10^{23}}{6.022\times 10^{23}}=1.19mol

Now we have to calculate the limiting and excess reagent.

The balanced chemical equation is:

3Mg+2H_3PO_4\rightarrow Mg(PO_4)_2+3H_2

From the balanced reaction we conclude that

As, 3 mole of Mg react with 2 mole of H_3PO_4

So, 0.553 moles of Mg react with \frac{2}{3}\times 0.553=0.369 moles of H_3PO_4

From this we conclude that, H_3PO_4 is an excess reagent because the given moles are greater than the required moles and Mg is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of H_2

From the reaction, we conclude that

As, 3 mole of Mg react to give 3 mole of H_2

So, 0.553 mole of Mg react to give 0.553 mole of H_2

Now we have to calculate the volume of H_2  gas at STP.

As we know that, 1 mole of substance occupies 22.4 L volume of gas.

As, 1 mole of hydrogen gas occupies 22.4 L volume of hydrogen gas

So, 0.553 mole of hydrogen gas occupies 0.553\times 22.4=12.4L volume of hydrogen gas

Therefore, the volume of hydrogen gas produced will be, 12.4 L

4 0
3 years ago
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