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3 years ago

!!DOUBLE QUESTION! HURRY! 50 PTS AND BRAINLIEST!!

Chemistry

1 answer:

Oksana_A [137]3 years ago

7 0

So basically the wavelength times the frequency of an electromagnetic wave equals the speed of light.

FYI,

λ

is the Greek letter lambda , and

ν

is the Greek letter nu (it is not the same as a v).

Answer:

Type of Radiation Frequency Range (Hz) Wavelength Range

gamma-rays 1020 - 1024 < 10-12 m

x-rays 1017 - 1020 1 nm - 1 pm

ultraviolet 1015 - 1017 400 nm - 1 nm

visible 4 - 7.5*1014 750 nm - 400 nm

near-infrared 1*1014 - 4*1014 2.5 μm - 750 nm

infrared 1013 - 1014 25 μm - 2.5 μm

microwaves 3*1011 - 1013 1 mm - 25 μm

radio waves < 3*1011 > 1 mm

(Ultraviolet I believe, not sure)

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Using the example in the above information determine the empirical formula of a compound if a sample contains 0.130 g of nitroge

olga2289 [7]

Answer: The empirical formula for the given compound is $NO_2$

Explanation : Given,

Mass of O = 0.370 g

Mass of N = 0.130 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.370g}{16g/mole}=0.0231moles$

Moles of Nitrogen = $\frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{0.130g}{14g/mole}=0.00928moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.00928 moles.

For Oxygen = $\frac{0.0231}{0.00928}=2.4\approx 2$

For Nitrogen = $\frac{0.00928}{0.00928}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of O : N = 2 : 1

Hence, the empirical formula for the given compound is $NO_2$

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