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Kazeer [188]
3 years ago
15

A centripetal force of 190 N acts on a 1,550-kg satellite moving with a speed of 5,300 m/s in a circular orbit around a planet.

What is the radius of its orbit?
Physics
1 answer:
kvasek [131]3 years ago
4 0

Answer:

Radius, r is equal to 229.16×10^6m

Explanation:

Given the following parameters;

Centripetal force on the satellite, Fc = 190N.

Mass of the satellite, M = 1,550-kg.

Speed of the satellite, V = 5,300m/s.

The relationship between a satellite of mass (m) moving in a circular orbit of radius (r) with a speed (v) and a centripetal force (Fc) is given by the equation;

Fc = (MV²)/r

Since, we're solving radius, r; we make "r" the subject of formula;

Thus, r = (MV²)/Fc

Substituting into the above equation;

r = (1550 × [5300]²)/190

r = (1550 × 28090000)/190

r = 43539500000/190

r = 229155263.16

Radius, r is equal to 229.16 × 10^6m

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