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babunello [35]
3 years ago
6

16. Cassandra notices that when she breathes on a cool window, the water vapor in her breath forms

Physics
1 answer:
choli [55]3 years ago
7 0

Answer: A

Explanation:I studied .

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A student in your class whom you kind-of like asks you come to watch a meteor shower. What exactly are you being invited to? a.
madam [21]

Answer:D. Watching the left-over dirt from a comet burn up by friction as the pieces hit the Earth's atmosphere

Explanation: A meteor shower is giant rocks moving across the sky

5 0
3 years ago
HELP PLS I WILL MARK U BRAINLIEST!!
Alex17521 [72]

Answer:

D

Explanation:

I would say much too small as there is a significant portion of the plant that is UNDER water.....

    (  Really depends on how deep the water is...if it is shallow water it would be just a little too small)

8 0
2 years ago
A resistor with resistance R is connected to a battery that has emf 13.0 V and internal resistance r = 0.350 Ω . For what two va
makvit [3.9K]

Answer:

R = 1,746 Ω

Explanation:

The power dissipated in the circuit is

   P = V I = V² / R

Let's find the current

   R = V² / P

Let's calculate

  R = 13²/81

   R = 2,096 Ω

This is total resistance

  R_total = R + r

   R = R_total - r

   R = 2,096 -0,350

   R = 1,746 Ω

8 0
3 years ago
What is the kinetic energy of a jogger with a mass of 70.8 kg traveling at a speed of 2.4 m/s?
BARSIC [14]
Kinetic energy equation is KE= 1/2mv^2. So plug in the numbers and you get a Kinetic Energy of 203.904 J
8 0
3 years ago
The state of strain at a point is plane strain with εx = ε0, εy = –2ε0, γxy = 0, where ε0 is a positive constant. What is the no
Marat540 [252]

Answer:

The normal strain along an axis oriented 45° from the positive x axis in the clockwise direction is -ε₀/2

Explanation:

Given that

\epsilon_{x}=\epsilon_{o}\\\\\epsilon_{y}=-2\epsilon_{o}\\\\\gamma_{xy}=0\\\\\theta=-45^{o}\\\\\epsilon_{x_{1}}=?

From equation of normal strain in x direction:

\epsilon_{x_{1}}=\epsilon_{x}cos^{2}\theta+\epsilon_{y}sin^{2}\theta+\gamma_{xy{ sin\theta cos\theta

Substituting the values:

\epsilon_{x_{1}}=\epsilon_{o}cos^{2}(-45)-2\epsilon_{o}sin^{2}(-45)+0\\\\\epsilon_{x_{1}}=\frac{\epsilon_{o}}{2}-2\frac{\epsilon_{o}}{2}\\\\\epsilon_{x_{1}}=-\frac{\epsilon_{o}}{2}

6 0
3 years ago
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