Answer:
25% colorblind daughter: 25% colorblind son: 25% carrier daughters with normal vision: 25% normal son.
Explanation:
The genotype of a color-blind man is X^cY and the genotype of the heterozygous carrier female is X^cX. A cross between X^cY and X^cX would produce a progeny in following ratio=
25% colorblind daughter: 25% colorblind son: 25% carrier daughters with normal vision: 25% normal son.
Therefore, the couple is likely to have 50% normal son and 50% affected son. Likewise, the couple is likely to have 50% normal daughters and 50% colorblind daughters.
Answer:
According to Lamarck, organisms altered their behavior in response to environmental change. ... Their changed behavior, in turn, modified their organs, and their offspring inherited those "improved" structures.
Answer:
They could all become some sort of food for people.
Explanation: Hope this helps! :)
I think the answer would be B
sorry if not
The two ways through which Eubacteria can reproduce are as follows:
- Binary fission and Conjugation.
Thus, the correct option for this question is C.
<h3>What is Eubacteria?</h3>
Eubacteria may be defined as a prokaryotic microorganism that primarily consists of a single cell that lacks a nucleus and contains DNA in a single circular chromosome. It also lacks other membrane-bound cell organelles.
During the process of binary fission, Eubacteria divide into two separate daughter cells through mitosis. While during the process of conjugation, two Eubacteria cells of the same or different species connect using the pili and exchange their genetic material.
Conjugation is partially considered a type of sexual mode.
Therefore, binary fission and conjugation are the two methods through which eubacteria can reproduce. Thus, the correct option for this question is C.
To learn more about Eubacteria, refer to the link:
brainly.com/question/2166240
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