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2 years ago

A system is said to be in a state of dynamic equilibrium when the

Chemistry

1 answer:

timama [110]2 years ago

7 0

Answer:

The correct option is D.

Explanation:

Chemical equilibrium refers to a state in which the concentration of both reactants and products are present in concentration which shows no tendency of changing with time. At this point there is no observable changes in the system. The chemical equilibrium will change to dynamic equilibrium once a reversible reaction occurs. In this case, the ratio of reactants or product changes but there are movements between the chemicals in such a way that there is no net change. At dynamic equilibrium, reactant and products are formed in a rate that keep the concentration of both constant.

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Do two objects with the same mass always have the same volume

Vika [28.1K]

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3 years ago

How many mol of C7H16 would you have if you have 76.36 grams? Give your answer to 2 decimal spaces.

tensa zangetsu [6.8K]

0.761 mol of $C_7H_{16}$ would you have if you have 76.36 grams.

A mole is defined as 6.02214076 × $10^{23}$ of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

Given data:

Mass=76.36 grams

$Moles = \frac{mass}{molar \;mass}$

$Moles = \frac{76.36 grams}{100.21 g/mol}$

Moles = 0.761

Hence, 0.761 mol of $C_7H_{16}$ would you have if you have 76.36 grams.

Learn more about moles here:

brainly.com/question/8455949

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2 years ago

Sometimes a nuclide is referenced by the name of the element followed by the:______

wolverine [178]

Answer:

The correct option is d

Explanation:

Nuclide is synonymous with groups of electrons or protons, that is, a nuclide is the grouping of nucleons.

6 0

3 years ago

How many grams of CO are needed to react with an excess of Fe2O3 to produce (210.3 g Fe) 209.7 g Fe? Show your work.

Fed [463]

Explanation:

$3CO(g)+Fe_2O_3(s)\rightarrow 2Fe(s)+3CO_2(g)$

1)Mass of CO when 210.3 g of Fe produced.

Number of moles of $Fe$ in 210.3 g=

$\frac{\text{Given mass of Fe}}{\text{Molar mass of Fe}}$

$=\frac{210.3}{55.84 g/mol}=3.76 mol$

According to reaction, 2 moles of Fe are obtained from 3 moles of CO, then 3.76 moles of Fe will be obtained from : $\frac{3}{2}\times 3.76 moles$ of CO that is 5.64 moles.

Mass of CO in 5.64 moles =

$\text{Number of moles}\times \text{molar mass of CO}=5.46\times 28 g/mol=157.92 g$

2)Mass of CO when 209.7 g of Fe produced.

Number of moles of $Fe$ in 209.7 g=

$\frac{\text{Given mass of Fe}}{\text{Molar mass of Fe}}$

$=\frac{209.7}{55.84 g/mol}=3.75 mol$

According to reaction, 2 moles of Fe are obtained from 3 moles of CO, then 3.75 moles of Fe will be obtained from : $\frac{3}{2}\times 3.75 moles$ of CO that is 5.625 moles.

Mass of CO in 5.625 moles =

$\text{Number of moles}\times \text{molar mass of CO}=5.625\times 28 g/mol=157.5 g$

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3 years ago

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According to this balanced equation, how many grams of water (H.0) form in

miskamm [114]

Answer:

your simpal answer is 177.32

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2 years ago

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