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nikdorinn [45]
3 years ago
8

This is hard, isn't it? please help me though. PLEASE

Chemistry
1 answer:
Liono4ka [1.6K]3 years ago
6 0
I think it might be A. i am not totally sure though
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One molecule is made of two or more _____ bonded together.
gayaneshka [121]

Answer:

              One molecule is made of two or more atoms bonded together.

Explanation:

                    Molecule is a substance which is made up chemically by two or more same or different atoms. The atoms joint together in a molecule due to a chemical bond. This chemical bond is formed either by mutual sharing of electrons or transfer of electrons between two atoms.

Examples:

A molecule of H₂O (water) is made up of two atoms of Hydrogen and one atom of Oxygen (H-O-H).

A molecule of CO₂ (Carbon Dioxide) is formed when a carbon atom is bonded to two oxygen atoms via a double bonds (O=C=O).

A  molecule of N₂ (Nitrogen Gas) is formed between two nitrogen atoms through a triple bond (N≡N).

5 0
3 years ago
Read 2 more answers
What is the smallest part of an element?
Ainat [17]
An atom is the smallest part of an element
4 0
3 years ago
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Classify the following substances as a Bronsted-Lowry acid, Bronsted-Lowry base, Lewis acid, and/or Lewis base.A. HCl, BF_3,B. C
ZanzabumX [31]

Answer:

A. HCl -> Bronsted-Lowry acid, BF3 -> Lewis acid

B. CCl3 -> Lewis acid, -HC -> Lewis acid or Bronsted-Lowry acid

C. H2O -> Bronsted-Lowry acid or Bronsted-Lowry base, CH3Cl -> Lewis base

D.-OCH3 -> Lewis base, NH3 -> Bronsted-Lowry acid or Lewis base.

Explanation:

For the Bronsted-Lowry theory, acids are the substances that can donate a proton H+ and bases are the substances that can receive a pronto H+.

For the Lewis theory, acid is the substance that can gain a pair of electrons, and the base is the substances that can donate the pair of electrons.

A. HCl -> The substance has a proton (H+) and it can donate it, so it's a Bronsted-Lowry acid. BF3 -> The boron (B), still has space in its shells to receive a pair of electrons, so it's a Lewis acid.

B. CCl3 -> The carbon didn't make all the bonds it can do (4), so it still can receive electrons, thus it's a Lewis acid. -HC-> It can lose the proton (H+) as a Bronsted-Lowry acid, os gains a pair of electrons at the carbon, as a Lewis acid.

C. H2O -> It can gain a proton and forms the ion H3O+, or it can lose a proton and form the ion OH-, so it can be a Brosted-Lowy acid or a Bronsted-Lowry base. CH3Cl -> It can donate pair of electrons (the hydrogen is to attached to the carbon, so it will not be lost), so it works as a Lewis base.

D. -OCH3 -> The oxygen still has pairs of electrons, which it can donate, so it's a Lewis base. NH3 -> It can gain a proton and forms the ion NH4+, so it'll be a Bronsted-Lowry acid, but the nitrogen still has electrons, which it can donate, working as a Lewis base.

6 0
3 years ago
A student mixes baking soda and vinegar in a glass. Are there any new substances created from this mixture?
Anni [7]

Answer:

Explanation:

1. A student mixes baking soda and vinegar in a glass. The results are shown at left. ... Yes I do belive that new substances are being formed because there is a chemical reaction between the baking soda and vinegar turning it into a bubbly substances instead of a powder and liquid.

4 0
3 years ago
"Thermite" reactions have been used for welding metal parts such as railway rails and in metal refining. One such thermite react
frosja888 [35]

<u>Answer:</u> The given reaction is non-spontaneous in nature.

<u>Explanation:</u>

Entropy change is defined as the difference in entropy of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate entropy change is of a reaction is:

\Delta S^o_{rxn}=\sum [n\times \Delta S^o_{(product)}]-\sum [n\times \Delta S^o_{(reactant)}]

For the given chemical reaction:

3Mg(s)+Cr_2O_3(s)\rightarrow 3MgO(s)+2Cr(s)

The equation for the entropy change of the above reaction is:

\Delta S^o_{rxn}=[(3\times \Delta S^o_{(MgO(s))})+(2\times \Delta S^o_{(Cr(s))})]-[(3\times \Delta S^o_{(Mg(s))})+(1\times \Delta S^o_{(Cr_2O_3(s))})]

We are given:

\Delta S^o_{(Mg(s))}=32.68J/K.mol\\\Delta S^o_{(Cr_2O_3(s))}=81.2J/K.mol\\\Delta S^o_{(MgO(s))}=26.94J/K.mol\\\Delta S^o_{(Cr(s))}=23.77J/K.mol

Putting values in above equation, we get:

\Delta S^o_{rxn}=[(3\times (26.94))+(2\times (23.77))]-[(3\times (32.68))+(1\times (81.2))]\\\\\Delta S^o_{rxn}=-50.88J/K=-0.0509kJ/K.mol

For the reaction to be spontaneous, the Gibbs free energy of the reaction must come out to be negative.

To calculate the standard Gibbs free energy of the reaction, we use the equation:

\Delta G^o=\Delta H^o-T\Delta S^o

where,

\Delta G^o = standard Gibbs free energy = ?

\Delta H^o = standard enthalpy change of the reaction = 665.1 kJ/mol

T = Temperature = 298.15 K

\Delta S^o = standard entropy change of the reaction = -0.0509 kJ/K.mol

Putting values in above equation, we get:

\Delta G^o=(665.1kJ/mol)-(298.15K\times (-0.0509kJ/K.mol))=680.27kJ/mol

As, the Gibbs free energy of the reaction is coming out to be positive, the reaction is non-spontaneous in nature.

Hence, the given reaction is non-spontaneous in nature.

4 0
4 years ago
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