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3 years ago

To balance a half-reaction in basic solution, you need to add enough of which substances to balance the equation?

2 answers:

4 0

I'm not sure if this is what you're looking for, but I suppose you would have to have the solute and the solution to balance the reaction.

gogolik [260]3 years ago

3 0

The answer is E. for plato users

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If five moles of a gas at a pressure of 5.4 kpa have a volume of 120 liters, what is the temperature?

ra1l [238]

<h3>The temperature is 15.58 kelvin </h3>

<em><u>Solution:</u></em>

<em><u>Ideal gas equation is given as:</u></em>

$PV = nRt$

Where,

P = pressure

V = volume

n = amount of substance

R = ideal gas constant

T = temperature

From given,

V = 120 liters

n = 5 moles

$R = 8.314\ \frac{Lkpa}{mol\ K}$

P = 5.4 kPa

T = ?

Therefore,

$5.4 \times 120 = 5 \times 8.314 \times T\\\\648 = 41.57 \times T\\\\T = 15.58\ kelvin$

Thus the temperature is 15.58 kelvin

4 0

2 years ago

The largest ruby isnthe world is 10.9 cm long, 9.1 cm wide and 5.8 cm thick, giving

Maslowich

You have to use density=mass/volume formula:

$3.97= \frac{x}{575}$

Solve for x and you get 2282.75 grams

6 0

2 years ago

20 ml each of oxygen and methane are allowed to react when the reaction is completed. The system now contains

Mekhanik [1.2K]

Answer:

CH4(g)+2O2(g)→CO2(g)+2H2O(l).

5 0

2 years ago

Which one of the following is not a valid expression for the rate of the reaction below? 4NH3 + 7O2 → 4NO2 + 6H2O Which one of t

Veseljchak [2.6K]

Answer : All of the above are valid expressions of the reaction rate.

Explanation :

The given rate of reaction is,

$4NH_3+7O_2\rightarrow 4NO_2+6H_2O$

The expression for rate of reaction for the reactant :

$\text{Rate of disappearance of }NH_3=-\frac{1}{4}\times \frac{d[NH_3]}{dt}$

$\text{Rate of disappearance of }O_2=-\frac{1}{7}\times \frac{d[O_2]}{dt}$

The expression for rate of reaction for the product :

$\text{Rate of formation of }NO_2=+\frac{1}{4}\times \frac{d[NO_2]}{dt}$

$\text{Rate of formation of }H_2O=+\frac{1}{6}\times \frac{d[H_2O]}{dt}$

From this we conclude that, all the options are correct.

3 0

2 years ago

If 1.27 moles of bromine gas (Br2) react with excess phosphorus (P), how many moles of phosphorus tribromide (PBr3) will be prod

frez [133]

Answer:

0.85 mole of PBr3.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

3Br2 + 2P —> 2PBr3

From the balanced equation above,

3 moles of Br2 reacted to produce 2 moles of PBr3.

Therefore, 1.27 moles of Br2 will react to produce = (1.27 x 2)/ 3 = 0.85 mole of PBr3.

Therefore, 0.85 mole of PBr3 is produced by the reaction.

8 0

3 years ago