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geniusboy [140]
3 years ago
12

The proprietor of a rock shop insists that a nugget is pure gold. if the nugget occupies a volume of 5.40 ml, what would its mas

s have to be if it were truly pure gold? (density gold = 19.3 g/ml)
Chemistry
1 answer:
statuscvo [17]3 years ago
7 0

Density of gold = 19.3 g/mL

Density can be calculated from volume and mass of a substance as follows,

Density = \frac{Mass}{Volume}

Given the volume of gold nugget = 5.40 mL

Calculating the mass of gold nugget from density and volume:

Density = \frac{Mass}{Volume}

Mass = Density * Volume

5.40 mL * 19.3 \frac{g}{mL} =104.22 g

Therefore, the mass of the nugget is 104.22 g

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Answer:

0.11mol/dm³

Explanation:

The reaction expression is given as:

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Volume of acid  = 25cm³  = 0.025dm³

Volume of base  = 18.4cm³ = 0.0184dm³

Concentration of base  = 0.15mol/dm³

Solution:

The concentration of hydrochloric acid = ?

 To solve this problem, let us first find the number of moles of the base;

 Number of moles  = concentration x volume

 Number of moles  = 0.15mol/dm³ x 0.0184dm³  = 0.00276mol

From the balanced reaction equation;

          1 mole of NaOH will combine with 1 mole of HCl

Therefore,  0.00276mol of the base will combine with  0.00276mol of HCl

 So;

  Concentration of acid  = \frac{number of moles }{volume}   = \frac{ 0.00276}{0.025}   = 0.11mol/dm³

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3 years ago
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