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Anit [1.1K]
4 years ago
11

How can different samples of one type of rock,such as marble, vary in physical properties

Chemistry
1 answer:
iogann1982 [59]4 years ago
3 0

https://do-work-zone.com/?mref=hello69

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Need help and people to show their work
AlekseyPX
It is 292.5 m because you do 4.5 hours times 65. (please give me brainliest)
6 0
3 years ago
Can someone please help me please dont scroll
Nostrana [21]
Quantitative is anything that is relating to a number value. Think “quantity”

Example:

1. There are 5 ml of water
2. There are 3 beakers
3. It takes 30 minutes for the reaction

Qualitative is about characteristics that can be described

Example

1. The liquid is green
2. The solution turned into a gas
3. Bubbles were produced
4 0
2 years ago
The further away from the sun a planet is, the hotter it is. <br><br> True<br> False
a_sh-v [17]

Answer:

False

Explanation:

The farther away a planet is, the colder it is.

7 0
3 years ago
Read 2 more answers
Plsss help with this ASAP TT
PSYCHO15rus [73]

Answer: lithium- 3 protons, 3 electrons, 3 neutrons

Oxygen- nucleon no. 16, Atomic no. 8, 8 protons, overall charge (-2)

Sorry I don't the others. Hope this helps

7 0
3 years ago
Two metals (Metal A and Metal B) are both exposed to a laser which emits photons that have a greater energy than the work functi
Tresset [83]

Answer:

shorter than

equal to

Explanation:

Let us go back to the Einstein photoelectric equation;

KE = E - Wo

Where

KE = kinetic energy of the photoelectron

E = energy of the incident photon

Wo = work function of the metal

But KE = 1/2mv^2

Thus the velocity of the emitted photoelectron  is determined by the kinetic energy of the emitted photoelectron.

Since the work function of metal A is smaller than that of metal B, the kinetic energy of photoelectrons emitted from metal A is greater than that of photoelectrons emitted from metal B . Therefore, the velocity of electrons from metal A is greater than those from metal B.

From de Broglie relation;

λ = h/mv

Where;

λ = de Broglie wavelength

h = Plank's constant

m = mass

v = velocity

Metal A producing electrons with greater velocity will lead to a shorter de Broglie wavelength compared to those from metal B.

The number of photoelectrons ejected is determined by the intensity of the photons and not the energy of the incident photons or the work function of the metals. Since the two metals are exposed to the the same laser, equal number of photoelectrons are produced for metals A and B.

8 0
3 years ago
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