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guapka [62]
3 years ago
9

Anyone able to answer this?

Mathematics
2 answers:
Anna71 [15]3 years ago
8 0

Answer:

(4,5)

Step-by-step explanation:

you can count the units, move seven to the right and two up

Ksivusya [100]3 years ago
3 0

Answer:

B) (4,5)

Step-by-step explanation:

Hope this helps.. (again)

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I need bro with this problem
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B^2=256 please help, urgent
Vlad [161]

Answer:

b = {-16, 16}

Step-by-step explanation:

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A=63°
bekas [8.4K]

Answer:

B. 7.35 inches

Step-by-step explanation:

In the triangle:

  • A=63°
  • c = 7.75 inch
  • B = 47°

Now we know that:

\angle A+\angle B+\angle C=180^\circ$ (Sum of angles in a \triangle)\\63^\circ+47^\circ+\angle C=180^\circ\\\angle C=180^\circ-(63^\circ+47^\circ)\\\angle C=70^\circ

Using the Law of Sines

\dfrac{a}{\sin A} =\dfrac{c}{\sin C}\\\\\dfrac{a}{\sin 63^\circ} =\dfrac{7.75}{\sin 70^\circ} \\\\a=\dfrac{7.75}{\sin 70^\circ} \times \sin 63^\circ\\\\a=7.35$ inches (to the nearest hundredth of an inch)

6 0
4 years ago
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Do one of the​ following, as appropriate.​ (a) Find the critical value z Subscript alpha divided by 2​, ​(b) find the critical v
babymother [125]

Answer:

We want to construct a confidence interval at 99% of confidence, so then the significance level would be 1-0.99 =0.01 and the value of \alpha/2 =0.005. And for this case since we know the population deviation is not appropiate use the t distribution since we know the population deviation and the best quantile assuming that the population is normally distributed is given by the z distribution.

And if we find the critical value in the normal standard distribution or excel and we got:

z_{\alpha/2}= \pm 2.576

And we can use the following excel code:

"=NORM.INV(0.005,0,1)"

Step-by-step explanation:

For this case we have the following info given:

\alpha=0.01, n =26, \sigma = 28.9

We want to construct a confidence interval at 99% of confidence, so then the significance level would be 1-0.99 =0.01 and the value of \alpha/2 =0.005. And for this case since we know the population deviation is not appropiate use the t distribution since we know the population deviation and the best quantile assuming that the population is normally distributed is given by the z distribution.

And if we find the critical value in the normal standard distribution or excel and we got:

z_{\alpha/2}= \pm 2.576

And we can use the following excel code:

"=NORM.INV(0.005,0,1)"

7 0
3 years ago
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