Answer:
Stretch is 0.816 m
Explanation:
Data :
Force = F = 10 N
Spring constant = k = 15 N/m
By using formula
F = - kx²
Where is displacement or stretch
x² = F/-k = 10/15 = 0.667
x ² = 0.667 ⇒ x=√o.667
x = 0.816 m
Answer:
0.256 J.
Explanation:
The formula for the energy stored in a capacitor is given as
E = 1/2CV².................... Equation 1
Where E = Energy stored in the capacitor, C = Capacitance of the capacitor, V = Voltage.
Make C the subject of the equation
C = 2E/V².................. Equation 2
Given: E = 64 mJ = 0.064 J, V = 1.5 V.
Substitute into equation 2
C = 2(0.064)/(1.5²)
C = 0.128/2.25
C = 0.0569 F.
If the capacitor where fully charged by 3.00 V.
E = 1/2CV²
Given: C = 0.0569 F, V = 3.0 V
Substitute into the equation above,
E = 1/2(0.0569)(3²)
E = 0.256 J.
Answer:
Maximum Tension=224N
Minimum tension= 64N
Explanation:
Given
mass =8 kg
constant speed = 6m/s .
g=10m/s^2
Maximum Tension= [(mv^2/ r) + (mg)]
Minimum tension= [(mv^2/ r) - (mg)]
Then substitute the values,
Maximum Tension= [8 × 6^2)/2 +(8×9.8)] = 224N
Minimum tension= [8 × 6^2)/2 -(8×9.8)]
=64N
Hence, Minimum tension and maximum Tension are =64N and 2224N respectively
Answer:
You answered your own question, I'm confused about what you're asking for.