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Nookie1986 [14]
4 years ago
7

A 1.50-V battery is used to charge a capacitor. When the capacitor is fully charged, it stores 64.0 mJ. If the capacitor were fu

lly charged by a 3.00-V battery instead, how much energy would it store?
Physics
2 answers:
marysya [2.9K]4 years ago
5 0
<h2>Answer:</h2>

256.05 mJ

<h2>Explanation:</h2>

The energy (E) stored in a capacitor when it is charged by a battery of voltage,V, is related to the capacitance, C, of the capacitor as follows;

E  = \frac{1}{2} x C x V²         ---------------(i)

<em>From the question;</em>

When a 1.50V battery is used, the energy is 64.0mJ. This means that when;

V = 1.50V, E = 64.0mJ = 0.064 J

<em>Substitute these values into equation (i) to find the capacitance of the capacitor as follows;</em>

0.064 = \frac{1}{2} x C x 1.5²

=> 0.064 = \frac{1}{2} x C x 2.25

=> 0.064 = 1.125 x C

=> C = \frac{0.064}{1.125}

<em>Solve for C;</em>

=> C = 0.0569F

Now, the we know the capacitance of the capacitor, let's calculate how much energy will be stored if the battery were 3.00V by substituting V = 3.00V and C = 0.0569 into equation (i) as follows;

E = \frac{1}{2} x 0.0569 x 3.00²  

E = \frac{1}{2} x 0.0569 x 9.00

E = 0.25605 J

<em>Multiply the result by 1000 to convert it to mJ. i.e;</em>

E = (0.25605 x 1000) mJ

E = 256.05 mJ

Therefore, the amount of energy it would store if the capacitor were fully charged by a 3.00V battery is 256.05 mJ

Leona [35]4 years ago
4 0

Answer:

0.256 J.

Explanation:

The formula for the energy stored in a capacitor is given as

E = 1/2CV².................... Equation 1

Where E = Energy stored in the capacitor, C = Capacitance of the capacitor, V = Voltage.

Make C the subject of the equation

C = 2E/V².................. Equation 2

Given: E = 64 mJ  = 0.064 J, V = 1.5 V.

Substitute into equation 2

C = 2(0.064)/(1.5²)

C = 0.128/2.25

C = 0.0569 F.

If the capacitor where fully charged by 3.00 V.

E = 1/2CV²

Given: C = 0.0569 F, V = 3.0 V

Substitute into the equation above,

E = 1/2(0.0569)(3²)

E = 0.256 J.

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Water flows through a horizontal nozzle in steady flow at the rate of 10m3/s. The inlet and outlet diameters are d1 = 0.5m and d2
Dvinal [7]

Answer:

P₁ = 2.215 10⁷ Pa, F₁ = 4.3 106 N,

Explanation:

This problem of fluid mechanics let's start with the continuity equation to find the speed of water output

        Q = A v

        v = Q / A

The area of ​​a circle is

       A = π r² = π d² / 4

Let's look at the speeds at each point

       v₁ = Q / A₁ = Q 4 /π d₁²

       v₁ = 10 4 /π 0.5²

       v₁ = 50.93 m / s

       v₂ = Q / A₂

       v₂ = 10 4 /π 0.25²

       v₂ = 203.72 m / s

Now we can use Bernoulli's equation in the colon

       P₁ + ½ ρ v₁² + ρ g y₁ = P₂ + ½ ρ v₂² + ρ g y₂

Since the tube is horizontal y₁ = y₂. The output pressure is P₂ = Patm = 1.013 10⁵ Pa, let's clear

       P₁ = P2 + ½ rho (v₂² - v₁²)

      P₁ = 1.013 10⁵ + ½ 1000 (203.72² - 50.93²)

      P₁ = 1.013 10⁵ + 2.205 10⁷

      P₁ = 2.215 10⁷ Pa

la definicion de presion es

      P₁ = F₁/A₁

     F₁ = P₁ A₁

     F₁ = 2.215 10⁷ pi d₁²/4

     F₁ = 2.215 10⁷ pi 0.5²/4

     F₁ = 4.3 106 N

     

6 0
3 years ago
26. Keenan found the mass of a book to be 4.56*10^ -2 kg . What is the mass of the book in milligrams?​
vagabundo [1.1K]

Taking into account the rule of three for the change of units, the mass of the book is 45600 miligrams.

First of all, the rule of three is a mathematical tool that helps you quickly solve proportionality problems.

Having three known values ​​and one unknown, a proportional relationship is established between all of them in order to find the fourth term of the proportion.

If the relationship between the magnitudes is direct (when one magnitude increases, so does the other; or when one magnitude decreases, so does the other), the rule of three is applied as follows, where a, b and c are known values ​​and x is the unknown to calculate:

a → b

c → x

So: x=\frac{cxb}{a}

Being 1 kg equivalent to 1000000 milligrams, In this case the rule of three is applied as follows: if 1 kg equals 1000000 milligrams, 4.56×10⁻² kg equals how many milligrams?

1 kg → 1000000 milligrams

4.56×10⁻² kg  → x

So:

x=\frac{4.56x10^{-2} kg x1000000 miligrams }{1 kg}

<u><em>x=45600 miligrams</em></u>

In summary, the mass of the book is 45600 miligrams.

Learn more:

  • <u>brainly.com/question/4805238?referrer=searchResults</u>
  • <u>brainly.com/question/5025657?referrer=searchResults</u>
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