The question is incomplete, here is the complete question:
The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.
When will there be less than 1 g remaining?
<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.
<u>Step-by-step explanation:</u>
All radioactive decay processes follow first order reaction.
To calculate the rate constant by given half life of the reaction, we use the equation:
where,
= half life period of the reaction = 46 days
k = rate constant = ?
Putting values in above equation, we get:
The formula used to calculate the time period for a first order reaction follows:
where,
k = rate constant =
t = time period = ? days
a = initial concentration of the reactant = 12.6 g
a - x = concentration of reactant left after time 't' = 1 g
Putting values in above equation, we get:
Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.
Answer:
A
Step-by-step explanation:
multiplication is the inverse of division and subtraction is the inverse of addition
An apothem is a line drawn from the centerpoint of the polygon to one side of the polygon. There is a formula for area in terms of apothem:
A = (1/2)*(Perimeter)*(Apothem)
The perimeter of the regular hexagon is just the length of one side multiplied with the number of sides. Since a hexagon has 6 sides,
P = 6(15) = 90in
A = 1/2 * 90 * 13
A = 585 square inches
Answer:
49 minutes
Step-by-step explanation:
To find the average time the machine was down per day, we need to add up the total time taken and then divide by the number of days. Since there are 5 days, we have:

= 49
So, the average time per day is 49 minutes.
Hope this helped! :)
Answer:
22.50
Step-by-step explanation:
if one mile is 1.50 then just do 1.50*14 which gives you 22.50