As the temperature of a gas increases, the average kinetic energy of the gas particles increases and the average speed of a gas particle increases.
According to the kinetic theory of gases, all gases are made of microscopic molecules that move in straight lines until they bump into another gas molecule or object. This transfer of energy causes molecules to move around faster and bump into each other more.
Kinetic energy is proportional to the speed of the molecules. As the speed of the colliding molecules increases, so does the total kinetic energy of all the gas molecules. It's pretty difficult to measure the speed of an individual gas molecule.
Instead, temperature can be used as a measure of the average kinetic energy of all the molecules in the gas. As the gas molecules gain energy and move faster, the temperature goes up. This is why Amy feels warmer!
To determine the average kinetic energy of gas molecules, we need to know the temperature of the gas, the universal gas constant (R), and Avogadro's number (NA).
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Answer:
See explanation
Explanation:
Molar mass is obtained as the sum of relative atomic masses as follow;
For CaBr = 40.08 + 79.90 = 119.98 g/mol
For BeBr = 9.012 + 79.90 = 88.912 g/mol
For CdBr2 = 112.41 + 2(79.90) = 272.21 g/mol
For CuBr2 = 63.55 + 2(79.90) = 223.35 g/mol
Answer:
The mass of 3.491 × 10¹⁹ molecules of Cl₂ of Cl₂ is 4.11 × 10⁻³ grams
Explanation:
The number of particles in one mole of a substance id=s given by the Avogadro's number which is approximately 6.023 × 10²³ particles
Therefore, we have;
One mole of Cl₂ gas, which is a compound, contains 6.023 × 10²³ individual molecules of Cl₂
3.491 × 10¹⁹ molecules of Cl₂ is equivalent to (3.491 × 10¹⁹)/(6.023 × 10²³) = 5.796 × 10⁻⁵ moles of Cl₂
The mass of one mole of Cl₂ = 70.906 g/mol
The mass of 5.796 × 10⁻⁵ moles of Cl₂ = 70.906 × 5.796 × 10^(-5) = 4.11 × 10⁻³ grams
Therefore;
The mass of 3.491 × 10¹⁹ molecules of Cl₂ of Cl₂ = 4.11 × 10⁻³ grams.
5.6L of O2 means we have 0.25 moles of O2.
As, 1 mole has 6.023*10^23 molecules,
0.25 moles of O2 will have 0.25*6.023*10^23 molecules=1.50575*10^23 molecules
and as 1 molecule of O2 has 2 atoms, so, 1.50575*10^23 molecules will have 2*1.50575*10^23 atoms=3.0115*10^23 atoms of O.
