Question

The volume, in liters, occupied by 2.50 moles of N2 gas. calculate at STP

Answer 1

Answer: The volume occupied by 2.50 moles of $N_2$ gas at STP is 56.0L

Explanation:

According to ideal gas equation:

$PV=nRT$

P = pressure of gas = 1 atm (at STP)

V = Volume of gas = ?

n = number of moles = 2.50

R = gas constant =$0.0821Latm/Kmol$

T =temperature =$273K$  (at STP)

$V=\frac{nRT}{P}$

$V=\frac{2.50mol\times 0.0821Latm/K mol\times 273K}{1atm}=56.0L$

Thus the volume occupied by 2.50 moles of $N_2$ gas at STP is 56.0L