Explanation:
the above process is done in very detail .
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The volume, in liters, occupied by 2.50 moles of N2 gas. calculate at STP
1 answer:
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Answer:
34.6g
Explanation:
Given parameters:
Mass of Octane = 11.2g
Reaction expression;
2C₈H₁₈ + 25O₂ → 16CO₂ + 18H₂O
Mass of octane = 11.2g
Unknown:
Mass of carbon dioxide produced = ?
Solution:
From the balanced reaction equation;
2 mole of octane produced 16 moles of carbon dioxide
From the given specie, let us find the number of moles;
Number of moles =
Molar mass of C₈H₁₈ = 8(12) + 18(1) = 114g/mole
Number of moles of octane = = 0.098mole
2 mole of octane produced 16 moles of carbon dioxide
0.098 mole of octane will produce = 0.79mole of CO₂
Mass of CO₂ = number of moles x molar mass
Molar mass of CO₂ = 12 + 2(16) = 44g/mol
Mass of CO₂ = 0.79 x 44 = 34.6g