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Vanyuwa [196]
4 years ago
6

The volume, in liters, occupied by 2.50 moles of N2 gas. calculate at STP

Chemistry
1 answer:
kondaur [170]4 years ago
6 0

Answer: The volume occupied by 2.50 moles of N_2 gas at STP is 56.0L

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 1 atm (at STP)

V = Volume of gas = ?

n = number of moles = 2.50

R = gas constant =0.0821Latm/Kmol

T =temperature =273K  (at STP)

V=\frac{nRT}{P}

V=\frac{2.50mol\times 0.0821Latm/K mol\times 273K}{1atm}=56.0L

Thus the volume occupied by 2.50 moles of N_2 gas at STP is 56.0L

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