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andrew11 [14]
4 years ago
5

How is a tendon different from a ligament

Chemistry
2 answers:
Vaselesa [24]4 years ago
6 0

Tendons connect muscle to bone. Ligaments connect bone to bone.

If you need more info I can give some more.

Hope this helps

Lera25 [3.4K]4 years ago
6 0

Tendons may also attach muscles to structures such as the eyeball. A tendon serves to move the bone or structure. A ligament is a fibrous connective tissue which attaches bone to bone, and usually serves to hold structures together and keep them stable

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Nitrous acid, hno2, has a ka of 7. 1 ✕ 10-4. what are [h3o ], [no2-], and [oh -] in 0. 40 m hno2?
romanna [79]

Nitrous acid, hno2, has an acid dissociation constant - ka of 7. 1 ✕ 10-4. what are [h3o ], [no2-], and [oh -] in 0. 40 m hno2 - 4829 M [OH^-] = 1.439 x 10^-14 M

The acid dissociation constant (Ka) is used to differentiate between strong and weak acids. Strong acids have very high Ka values. The Ka value is determined by examining the equilibrium constant for acid dissociation. The acid dissociates more readily as the Ka increases.

The original molecular definition of an acid, according to Arrhenius, is a molecule that dissociates in an aqueous solution, releasing the hydrogen ion H+ (a proton): HA A + H+. acid dissociation constant is an equilibrium constant for this dissociation reaction.  

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4 0
2 years ago
How many moles of oxygen are present in 16 g of oxygen gas​
makkiz [27]
Hope this helps

Answer- 1 mole
4 0
3 years ago
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What happens to the length of shadows as noon approaches on a sunny day?
Tems11 [23]

Answer:

The answer is D

5 0
3 years ago
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In a carbon-carbon triple bond, what is the nature of the bonding between the carbons?
maxonik [38]
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4 0
3 years ago
A patients blood is tested for growth hormone which has a molecular mass of 848.952g/mol. The test results show a normal concent
rusak2 [61]

Answer:

\boxed{4.7\times 10^{-9}}

Explanation:

Data:

MM = 848.952 g/mol  

   c = 4.0 x 10⁻⁶ g/L

  V = 1 L

Calculations:

(a) Mass of growth hormone

\text{Mass} = \text{1 L} \times \dfrac{4.0 \times 10^{-6} \text{ g}}{\text{1 L}} = 4.0 \times 10^{-6} \text{ g}

(b) Moles of growth hormone

\text{Moles} = 4.0 \times 10^{-6} \text{ g} \times \dfrac{\text{1 mol}}{\text{848.952 g}} = 4.7\times 10^{-9}\text{ mol}\\\\\text{There are $\boxed{\mathbf{4.7\times 10^{-9}}\textbf{ mol}}$ of growth hormone in 1 L of blood.}

8 0
3 years ago
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